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Sonbull [250]
4 years ago
6

If sin x = .42, what is cos x?

Mathematics
1 answer:
34kurt4 years ago
6 0
From the identity,
sin^2(x)+cos^2(x)=1
then 
cos(x)=sqrt(1-sin^2(x))
where sin(x) is given as 0.42.

Note that the above answer applies to 0<x<90 degrees
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3 years ago
Let gbe a function such that g(x) = -2r + 5 and is defined on the domain (-1,3) State the range of this function in interval not
Paladinen [302]

Answer:

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Step-by-step explanation:

Given the function

g(x) = -2r+5

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Putting x = -1

g(x)=-2r+5

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      = 2+5

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Putting x = 0

g(x)=-2r+5

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      =0+5

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Putting x = 1

g(x)=-2r+5

      = -2(1)+5

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      =-4+5

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Putting x = 3

g(x)=-2r+5

      = -2(3)+5

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      = -1

Thus the range interval is: (7, -1)

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8 0
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Read 2 more answers
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