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Sonbull [250]
3 years ago
6

If sin x = .42, what is cos x?

Mathematics
1 answer:
34kurt3 years ago
6 0
From the identity,
sin^2(x)+cos^2(x)=1
then 
cos(x)=sqrt(1-sin^2(x))
where sin(x) is given as 0.42.

Note that the above answer applies to 0<x<90 degrees
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We saw two distributions for triathlon times: N (μ = 4313, σ = 583) for Men, Ages 30 - 34 and N (μ = 5261, σ = 807) for the Wome
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Hello!

Using the information of the triathlon times of men and women you have to find:

a. The cutoff time for the fastest 5% men, if the times of the male triathletes have a normal distribution, this value will separate the top 5% from the rest of the distribution, symbolically:

P(X≥x₀)= 0.05

Where x₀ represents the cutoff time that you need to find.

Now if this value has 5% of the distribution above it, then 95% of the distribution will be below it, symbolically:

P(X<x₀)= 0.95

Next is to use the standard normal distribution, you have to find the Z value that accumulates 0.95 of probability: P(Z<z₀)= 0.95

z₀= 1.648

Using the formula: Z= (X-μ)/δ what is left to do is to reverse the standardization and reach the value of the variable:

z₀= (x₀-μ)/δ

x₀= (z₀*δ)+μ

x₀= (1.648*583)+4313

x₀= 5273.784 seconds

The cutoff time for the fastest 5% is 5273.784 seconds.

b. The cutoff time for the slowest 10% women, if you are taking the "slowest" into account, then this is the lowes 10% of the distribution. Meaning that the value of time separates the "lowest" 10% of the distribution from the rest, symbolically:

P(X≤x₀)=0.10

Same as before, you have to use the standard normal distribution:

P(Z≤z₀)= 0.10

z₀= - 1.283

Now using this value you have to reverse the standardization:

z₀= (x₀-μ)/δ

x₀= (z₀*δ)+μ

x₀= (-1.283*807)+5261

x₀= 4225.619 seconds

The cutoff time for the slowest 10% is 4225.619 seconds.

I hope it helps!

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Evaluate <br>2000(0.085)<br>3200(0.045)(8)<br>Please help fast!
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I also put this on your last post
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