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Luda [366]
3 years ago
5

The position of an object at time t is given by s(t) = 3 - 4t. Find the instantaneous velocity at t = 8 by finding the derivativ

e.
Mathematics
2 answers:
ioda3 years ago
8 0
Answer: - 4


Explanation: 

As the question tells, the instantaneous velocity is the first derivative of the position.


1) position equation given: s(t) = 3 - 4t

2) derivative, v(t) = s'(t)

s'(t) = [ 3 - 4t]' = (3)' - (4t)' = 0 - 4(t') = - 4

3) Then, the velocity is constant (does not depends on t), and its value is - 4.

zysi [14]3 years ago
7 0
For this case, we have that the equation of the position is given by:
 s (t) = 3 - 4t

 To find the velocity, we must derive the equation from the position.
 We have then:
 s' (t) = - 4

 Then, we evaluate the derivative for time t = 8.
 We have then:
 s' (8) = - 4
 Answer:
 
the instantaneous velocity at t = 8 is:
 
s' (8) = - 4
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Show that (3+4)2−(3−4)2−(4)(4)=32
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Answer:

Explanation below

Step-by-step explanation:

(3+4)= 7

7+2 = 9

-(3-4) (Invisible one)

-3+4 add to the 9

10

10+2= 12

12-4=8

8×4 =32

Sorry if this seems a bit confusing, but its quite hard to show the process without paper.

Hope this helps! :)

8 0
3 years ago
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Step-by-step explanation:

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3 years ago
Below is the graph of y=b^x. Find b.
omeli [17]
Y = <span>b^x

when x = 1
y = b^1
y  = b

Therefore, the value of b is the same as the value of y when x =1
From the graph,
When x = 1, y = 0.5
Therefore, b = 0.5


To confirm this

From the graph,

When x = -1, y = 2
Since </span>y = b^x<span>
2 = </span>b^-1
2 = 1/b
2b = 1
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When x = -2, y = 4
Since y = b^x
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4 = 1/(b^2)
b^2 = 1/4
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b = 1/2
b = 0.5

Therefore, it is conformed that b = 0.5

5 0
2 years ago
Read 2 more answers
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