Answer:
Step-by-step explanation:
given that the operations manager of a plant that manufactures tires wishes to compare the actual inner diameter of two grades of tires, each of which has a nominal value of 575 millimeters. A sample of five tires of each grade is selected, and the results representing the inner diameters of the tires, ranked from smallest to largest, are as follows:
Grade X
568 570 575 578 584
Mean = Total/5 = 575
Median = middle entry = 575
Mode = nil
Grade Y
573 574 575 577 578
Mean = sum/5 = 575.4
Median = middle entry =575
Mode = nil
Answer:
-2
Step-by-step explanation:
To solve you need to replace the variables with their numbers.
3(-1) - (-1^2)
-1 x -1 = -1
3 x (-1) = -3
-3 - (-1) =
-2
(x-3)^2 + (x+5)^2=9^2
(x^2-6x+9) + (x^2+10x+25)=81
2x^2+4x+34=81
2x^2+4x-47=0
From here just use quadratic formula
Answer: A.) 21/5 but as a mixed number it's 4 1/5 B.) 175/24 but as a mixed number it's 7 7/24
Step-by-step explanation:
