The expression for the distance the car travels after t seconds is d = 200t + 50t²
<h3>Equation of motion </h3>
From the question, we are to write an expression for the distance the car travels after t seconds
From the given information,
The equation for the motion of an object with constant acceleration is
d = vt + 0.5at²
For the race car,
v = 200 ft/s
a = 100 ft/s²
Putting the parameters into the equation, we get
d = 200t + 0.5(100)t²
d = 200t + 0.5 ×100)t²
d = 200t + 50t²
Hence, the expression for the distance the car travels after t seconds is d = 200t + 50t²
Learn more on Equations of motion here: brainly.com/question/20910641
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Answer:
30 inches
Step-by-step explanation:
1 ft= 12 inches
12×2= 24
1/2 of 12 is 6
24+6=30
30 inches
Answer:
7789 i think this is the answer
Step-by-step explanation:
