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lyudmila [28]
3 years ago
13

Write 9n + 1 in a word phrase 9n +1

Mathematics
1 answer:
Lisa [10]3 years ago
6 0

Answer:

<u>Sum</u><u> </u><u>o</u><u>f</u><u> </u><u>1</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>n</u><u>i</u><u>n</u><u>e</u><u>s</u><u> </u><u>t</u><u>i</u><u>m</u><u>e</u><u>s</u><u> </u><u>a</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u>

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A train leaves Ayr station every day at 09:50 and arrives in Glasgow at 10:39. How long is the journey?
Pepsi [2]

Answer:

49 minutes

Step-by-step explanation:

9:50 to 10:00 is 10 minutes

plus the 39 minutes in 10:39

10 + 39 = 49

hope i helped

4 0
3 years ago
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Who on connections academy can help me with the chaos and theory portfolio worksheet?
prisoha [69]

Answer:

not me :)

Step-by-step explanation:

6 0
3 years ago
How much faster is the 6 minutes 47.30 seconds time than the 6 minutes 52.01 seconds time?
lara31 [8.8K]

Answer:

25

Step-by-step explanation:

25 25

3 0
2 years ago
Q # 1 simplify the expression
Agata [3.3K]
<u>Answer</u>

95,040

<u>Explanation</u>
The interpretation of this expression is; the number of permutation of 5 objects out of 12.

12P5 = 12!/(12-5)!

         =12!/7!
         =(12×11×10×9×8×7×6×5×4×3×2×1)/(7×6×5×4×3×2×1)

         =12×11×10×9×8
         =95,040

5 0
3 years ago
You recently took a statistics exam in a large class. The instructor tells the class that the scores were Normally distributed,
Lunna [17]

Answer:

b. the area to the right of 2

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the area to the left of Z. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to the right of Z.

In this problem:

X = 96, \mu = 72, \sigma = 12

Z = \frac{X - \mu}{\sigma}

Z = \frac{96 - 72}{12}

Z = 2

Percentage who did better:

P(Z > 2), which is the area to the right of 2.

5 0
3 years ago
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