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Nostrana [21]
3 years ago
13

63% of a university's freshman class are majoring in Economics. If 3654 students in the freshman class are Economics majors, how

many students are in the freshman class?
Mathematics
1 answer:
Troyanec [42]3 years ago
3 0

Answer: 2302 students are in the freshman class.

Steps: Multiply 3,654 by .63 to find the percentage of students majoring in Economics.

Plz mark brainliest:)

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Perpendicular Vectors:
klemol [59]
1.
v x w = 8 i - 24 j + 15 k + 10 j - 12 i - 24 k =
= - 4 i - 14 j - 9 k
Answer: D )
2.
v x w = -16 i - 16 j - 18 k + 12 j + 48 i - 8 k =
= 32 i - 4 j - 10 k
Answer: C )
3.
The cross product:
< - 6, 7, 2 > x < 8, 5, -3 > =
= - 21 i + 16 j - 30 k - 18 j - 10 i - 56 k =
= - 31 j - 2 j - 86 k = < - 31, - 2, - 86 >
Vectors are perpendicular if: cos ( u, v ) = 0
< - 6 , 7. 2 > * < -31, - 2, - 86 > = 186 - 14 - 172 = 0
< 8, 5 , - 3 > * < - 31, - 2, - 86 > = -248 - 10 + 258 = 0
Answer: A ) < - 31, - 2 , - 86 >,  yes.
3 0
3 years ago
Part 1:
gladu [14]

Answer:

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7 0
2 years ago
5% of adults participate in at least 30 minutes of exercise each day. How likely is it that a randomly chosen adult will exercis
MaRussiya [10]

Answer:

5 out of 100 adults so not very likely

6 0
3 years ago
A baby weights 18 pounds at her four month appointment. Six months later she weights 24 pounds. By what percentage did the baby’
Anna11 [10]

Answer: 25%

Step-by-step explanation:

Given : Previous baby's weight = 18 pounds

New baby's weight =  24 pounds.

Increase in weight = New weight -Previews weight

=24 pounds - 18 pounds  =6 pounds

Percentage increase in baby's weight ==\dfrac{\text{Increase in baby's weight}}{\text{previous weight}}\times100

\\\\=\dfrac{6}{24}\times100=25\%

Hence, the percentage increase in baby's weight = 25%

4 0
3 years ago
If sum of first 6 digits of AP is 36 and that of the first 16 terms is 255,then find the sum of first ten terms.
Cloud [144]

Answer:

100

Step-by-step explanation:

We have the sum of first n terms of an AP,

Sn = n/2 [2a+(n−1)d]

Given,

36= 6/2 [2a+(6−1)d]

12=2a+5d ---------(1)

256= 16/2 [2a+(16−1)d]

32=2a+15d ---------(2)

Subtracting, (1) from (2)

32−12=2a+15d−(2a+5d)

20=10d ⟹d=2

Substituting for d in (1),

12=2a+5(2)=2(a+5)

6=a+5 ⟹a=1

∴ The sum of first 10 terms of an AP,

S10 = 10/2 [2(1)+(10−1)2]

S10 =5[2+18]

S10 =100

This is the sum of the first 10 terms.

Hope it will help.

4 0
3 years ago
Read 2 more answers
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