Ok so how you do it is on the left nearest to the example number line the compound equality would be x then “<“ this sign with the line under it, then “-3”. For the right side you would put “x > 2” respond if you have any questions

5 0

3 years ago

Write the equation of a line that passes through the point m(2,3) and has slope 1/2.

denis-greek [22]

Answer:

Step-by-step explanation:

$Equation \ of \ a \ line, (y-y_1)=slope(x-x_1)$

$(x_1, y_1) = (2,3)$

$y-3=\frac{1}{2}(x-2)\\\\y -3= \frac{1}{2}x-1\\\\y = \frac{1}{2}x-1+3\\\\y = \frac{1}{2}x+2$

4 0

3 years ago

The points (8,-16) and (6,-14) fall on a particular line. What is its equation in slope-intercept form?

Sonja [21]

Answer:

y = -x - 8

Step-by-step explanation:

First, calculate the slope:

m = $\frac{y2-y1}{x2-x1}$

(x₁, y₁) will be (8, -16)

(x₂, y₂) will be (6, -14)

Plug in values:

m = $\frac{-14 - -16}{6-8}$

simplify:

m = $\frac{2}{-2}$

m = -1

plug values into y = mx + b:

-16 = (-1)(8) + b

solve for b:

b - 8 = -16

b = -8

rewrite the equation:

y = -1x - 8

y = -x - 8

3 0

3 years ago

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