Graphed in attached file and drawn!
Answer:49 sec
Step-by-step explanation:
Given
Maximum speed to reach is 183.58 mi/h
Length of course is 5 mi
acceleration rate is defined by 60mi/h in 4 sec
therefore acceleration(a)


To reach a speed of 183.58mi/h with an acceleration of 
Using equation of motion
v=u+at


t=0.00339 hours
t=12.23 s reach maximum speed
To complete course it takes


t=0.01360 hour
or 
The value of x would be 4m
Answer:
a and b
Step-by-step explanation:
Answer:
- 3x² is a term in the numerator
- x + 1 is a common factor
- The denominator has 3 terms
Step-by-step explanation:
You can identify terms and count them before you start factoring. Doing so will identify 3x² as a term in the numerator, and will show you there are 3 terms in the denominator.
When you factor the expression, you get ...

This reveals a common factor of x+1.
So, the above three observations are true of this rational expression.