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2 years ago

Need help asap which of the following exponential function the graph below

Mathematics

1 answer:

lesantik [10]2 years ago

8 0

Answer:

i believe the answer is B

Step-by-step explanation:

Hope this helps

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What is the equation in slope-intercept form of the line that passes through the point (5, 0) and is parallel to the line repres

alisha [4.7K]

Answer:

y=1.2x-5

Step-by-step explanation:

Parallel lines are equal lines that never intersect or touch each other.

When a problem gives you information about the line being parallel to another, you'll know the slope of the line is going to be the same.

3 0

2 years ago

A number cube has sides numbered 1though 6 the probability of rolling a 2 is

sammy [17]

This is 1/2)2=1/4 hope this helps

7 0

3 years ago

Simpl following 12mn+4m²n-3mn+2m²n

almond37 [142]

Answer:

9m+6m^2n

Step-by-step explanation:

12mn-3mn=9mn

4m^2n+2m^2n=6m^2n

==> 9m+6m^2n

or rewrite as 3m(3+2mn)

5 0

3 years ago

Read 2 more answers

An equation of the perpendicular bisector of the line segment with end points (3,0) and (-3,0) is

Norma-Jean [14]

Answer:

$x = 0$

Step-by-step explanation:

Given

$(x_1,y_1) = (3,0)$

$(x_2,y_2) = (-3,0)$

Required

The equation of the perpendicular bisector.

First, calculate the midpoint of the given endpoints

$(x,y) = 0.5(x_1 + x_2, y_1 + y_2)$

$(x,y) = 0.5(3-3, 0+ 0)$

$(x,y) = 0.5(0, 0)$

Open bracket

$(x,y) = (0.5*0, 0.5*0)$

$(x,y) = (0, 0)$

Next, determine the slope of the given endpoints.

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{0 - 0}{-3- 3}$

$m = \frac{0}{-6}$

$m = 0$

Next, calculate the slope of the perpendicular bisector.

When two lines are perpendicular, the relationship between them is:

$m_2 = -\frac{1}{m_1}$

In this case:

$m = m_1 = 0$

So:

$m_2 = -\frac{1}{0}$

$m_2 = unde\ fined$

Since the slope is $unde\ fined$ , the equation is:

$x = a$

Where:

$(x,y) = (a,b)$

Recall that:

$(x,y) = (0, 0)$

So:

$a = 0$

Hence, the equation is:

$x = 0$

5 0

3 years ago

Which statement is true about the given function? f(x) < 0 over the intervals (–infinity, –2.7) and (0.8, infinity). f(x) &lt

Lesechka [4]

Answer: f(x) < 0 over the intervals (–infinity, –2.7) and

(–1, 0.8).

Step-by-step explanation:

I got it right

8 0

3 years ago

Read 2 more answers