Answer:i'm pretty sure its C: into cells
Explanation:
<span>Python is Highly case sensitive language. We can use > , < , <= , <= , == , != to compare two strings. Python compares string using ASCII value of the characters.
For example name as "MIDHUN" and name1 as "Midhun" . The first two characters from name and name1 ( M and M ) are compared. As they are equal, the second two characters are compared. Since the ASCII values are not equal the result is not equal.</span>
<span>The correct answer is B. Insertion. In this particular insertion there is an insert of three bases. Complementary strands in DNA are the opposite strand, so Adenine is coupled to Thymine and Guanine is coupled to Cytosine. So the complementary sequence (also called the antisense strand) of the original would be GTC GGC ATC, there's an extra 3 bases in there: ACA.</span>
Answer:
cryosphere and atmosphere seems like it.
Explanation:
Answer:
See the explanation
Explanation:
Answer 1.
As given that in F1 all are short and white then it can be said according to Mendel's law that short and white are dominant over tall and purple.
Let S for short s for tall and W for white and w for purple allele.
So the genotype of short purple will be Ssww or SSww. So In first case Ssww self crossed then resultant offsprings will be,
................ Sw .................... sw
Sw ........ SSww ............. Ssww
sw ........ Ssww .............. ssww (tall and purple)
So from this 1/4 will be tall and purple while 3/4 will be short and purple.
In second case SSww only short purple progeny will appear.
Answer 2.
2. a) The female progeny will not show any trait because there are two X chromosome in females , so female offspring can be carrier but not show any trait in case of X- linked trait.
2. b) Half of male offsprings show trait because X is inherited from mother. So the chance of having X-linked recessive allele is 1/2.
2. c) The chance of having X linked affect allele in daughter is 1/2. So the chance of inheriting that X to son will be 1/2 so in total there is chance of 1/4 that son will be affected.
2. d) the chance of first child show this trait will be 1/4 in case of male offspring while 0 in case of female offspring.
Hope this helps!
