Use the equation below to find y, if m=2, x=8, and b=3.y=mx+by =
1 answer:
You might be interested in
The horizontal distance traveled by the projectile is given as
where
V₀ = initial velocity, m/s
Note that
sin(2θ) = 2sinθ cosθ
Therefore, the horizontal distance traveled is
Because V₀ = 52 m/s, in order to travel a horizontal distance of 200 m, the correct equation to determine θ is
(52²/9.8) sin(2θ) = 200
or
275.92 sin(2θ) = 200
Answer: A
where
V₀ = initial velocity, m/s
Note that
sin(2θ) = 2sinθ cosθ
Therefore, the horizontal distance traveled is
Because V₀ = 52 m/s, in order to travel a horizontal distance of 200 m, the correct equation to determine θ is
(52²/9.8) sin(2θ) = 200
or
275.92 sin(2θ) = 200
Answer: A
Hello!
Recall that the transformations form of a parabola is:
f(x) = ±a(b(x-h)) + k where:
a = vertical stretch/compression
b = horizontal stretch/compression
h = horizontal shift, x-coordinate of vertex
k = vertical shift, y-coordinate of vertex
In this instance, the parent function is f(x) = 3x^2. There is a vertical stretch of 3.
However, there is a point (7, -2) that needs to be included. Substitute these values into the transformation formula:
h = 7
k = -2
f(x) = 3(x - 7)² - 2 is the equation with (7, -2) as the vertex.