Triangle LMN was dilated by a scale factor of 2 followed by a translation 1 unit right and 3 unit up to form triangle L'M'N'
<h3>What is
transformation?</h3>
Transformation is the movement of a point from its initial location to a new location. Types of transformations are<em> reflection, translation, rotation and dilation.</em>
Rigid transformation preserves the shape and size of the figure. <em>Reflection, translation, rotation</em> are rigid transformations.
Triangle LMN was dilated by a scale factor of 2 followed by a translation 1 unit right and 3 unit up to form triangle L'M'N'
Find out more on transformation at: brainly.com/question/4289712
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Answer:
g(x) = -6 - 3x
f(x) = X^6
Step-by-step explanation:
It's <span>Diophantine equation.
First, we need to found gcd(6,(-2)):</span>
6=2*3
(-2)=(-1)*2
So, gcd(6,-2)=2
Now, the question is. Can we dived c=24, by gcd(6,-2) and in the end get integer?
Yes we can.
![\frac{24}{2} =12](https://tex.z-dn.net/?f=%20%5Cfrac%7B24%7D%7B2%7D%20%3D12)
So, we can solve it.
Now is the formula:
![{\displaystyle {\begin{cases}x=x_{0}+n{\frac {b}{\gcd(a,\;b)}}\\y=y_{0}-n{\frac {a}{\gcd(a,\;b)}}\end{cases}}\quad n\in \mathbb {Z} .}](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20%7B%5Cbegin%7Bcases%7Dx%3Dx_%7B0%7D%2Bn%7B%5Cfrac%20%7Bb%7D%7B%5Cgcd%28a%2C%5C%3Bb%29%7D%7D%5C%5Cy%3Dy_%7B0%7D-n%7B%5Cfrac%20%7Ba%7D%7B%5Cgcd%28a%2C%5C%3Bb%29%7D%7D%5Cend%7Bcases%7D%7D%5Cquad%20n%5Cin%20%5Cmathbb%20%7BZ%7D%20.%7D)
Second, we need the first pair (x0,y0)
if
x=0
then
![y=(-12)](https://tex.z-dn.net/?f=y%3D%28-12%29)
Third, we gonna use that formula:
![{\displaystyle {\begin{cases}x=-n}\\y=-3(4+n)}\end{case}\quad n\in \mathbb {Z} .}](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20%7B%5Cbegin%7Bcases%7Dx%3D-n%7D%5C%5Cy%3D-3%284%2Bn%29%7D%5Cend%7Bcase%7D%5Cquad%20n%5Cin%20%5Cmathbb%20%7BZ%7D%20.%7D)
Congratulations! We solve it.
Answer:
4,099 and 5,011
Step-by-step explanation:
This problem can be solved by taking options one by one.
Option (1) : 4,099
Digit in ones place = 9
The value of the digit in tens place = 90
. It is correct.
Option (2) : 4,110
Digit in one places = 0
The value of the digit in tens place = 10
It is incorrect.
Option (3) : 5,909
Digit in one places = 9
The value of the digit in tens place = 0
It is again incorrect.
Option (4) : 5,011
Digit in one places = 1
The value of the digit in tens place = 10
. It is correct.
Hence, in option (a) and (d), the he ones place is 1/10 the value of the digit in the tens place.