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3 years ago

david spent 2/5 of his money on a storybook. The storybook cost $20. How much money did he have at first

2 answers:

6 0

If the storybook cost $20, and it was also 2/5 of his money, then 2/5 of his money is $20. In other words:
2x/5 =20.

Multiplying both sides by 5, we get:
2x = 100.

If we divide both sides by 2, then we're left with:
x = 50.

David had $50 at first.

arlik [135]3 years ago

3 0

50 dallors hope this help

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The value of a machine, V, at the end of t years is given by V = C(1 - 1)', where is the original cost and r is the rate of depr

NNADVOKAT [17]

Answer:

The value of the machine after two years is approximately $466.6

Step-by-step explanation:

The details of the valuation of the machine are;

The function giving the machine value, 'V', is V = $C \cdot (1 - r)^t$

Where;

C = The original cost of the machine

r = The depreciation rate

t = The time the machine has been in service

When C = $576, r = 0.1, t = 2 years, we have;

$V = 576 \times (1 - 0.1)^2 = 466.56$

Therefore, the value of the machine that costs $576 having a depreciation of 0.1 after 2 years is, V = $466.58

By rounding to the nearest cent, we have, V = $466.6.

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3 years ago

Which complex number does not lie on the line segment

mihalych1998 [28]

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3 years ago

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charle [14.2K]

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3 years ago

Suppose Pr(A)=0.25 and Pr(B)=0.48, where A and B are mutually exclusive. Find Pr(A ? B).

Slav-nsk [51]

Answer: The required value is P(A ∪ B) = 0.73.

Step-by-step explanation: Given that A and B are two mutually exclusive events where

$P(A)=0.25~~~\textup{and}~~~P(B)=0.48$

We are to find the following probability :

P(A ∪ B).

We know that

the intersection of two mutually exclusive events is null event. That is,

A ∩ B = ∅ ⇒ P(A ∩ B) = 0.

From the laws of probability, we have

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=0.25+0.48-0=0.73$

Thus, the required value is P(A ∪ B) = 0.73.

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4 years ago

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Watch this,it might help.

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