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dexar [7]
3 years ago
9

¿Qué pasa cuando nos enfrentamos con dos incógnitas, en el caso de que las ecuaciones que se generen sean de primer grado y form

en un sistema de ecuaciones?
Mathematics
1 answer:
kolbaska11 [484]3 years ago
7 0
<h2>Explicación:</h2><h2 />

Una ecuación de primer grado es una ecuación lineal en la que se ven involucradas una o más variables, sin existir productos entre ellas. Por ejemplo, una ecuación de primer grado con dos incógnitas es:

y=mx+b \\ \\m:pendiente \\ \\ b:y-intercept

De manera que un sistema de ecuaciones con dos incógnitas podría ser:

y=m_{1}x+b_{1} \\ \\ y=m_{2}x+b_{2}

que representan ecuaciones de rectas.

Existen tres posibilidades:

1. Una solución:

Ocurre cuando las rectas no son paralelas, es decir:

m_{1}\neq m_{2}

Entonces la solución es la intersección de estas dos rectas.

2. Infinitas soluciones:

Ocurre cuando las ecuaciones son las mismas, en cuyo caso las rectas son las mismas y se intersectan en todos los puntos, es decir:

m_{1}=m_{2} \\ \\ b_{1}=b_{2}

3. Ninguna solución:

Ocurre cuando las rectas son paralelas pero tienen distinta intersección con el eje y, es decir:

m_{1}=m_{2} \\ \\ b_{1}\neq b_{2}

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Answer:

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Step-by-step explanation:

Given

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Where Length = 20 ft

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Required

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We'll assume that the room is rectangular in shape and all 4 sides are covered.

<em>This means that Mickey will paint 4 walls and 1 ceiling.</em>

The dimension of the 2 of the 4  walls is as follows;

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Because opposite sides of a rectangle are equal, the dimension of the remaining 2 walls is: 20ft by 10ft, 25ft by 10ft

Calculating the area of the 4 walls;

Area = 20ft * 10ft + 25ft * 10ft + 20ft * 10ft + 25ft * 10ft

Area = 200ft^2 + 250ft^2 + 200ft^2 + 250ft^2

Area = 900ft^2

The dimension of the ceiling is as follows:

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Calculating the area of the ceiling

Area = 20ft * 25ft

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So, the area Micky will cover = Area of 4 walls + Area of ceiling

Total Surface Area = 900ft^2 +500ft^2

Total Surface Area = 1400ft^2

Hence, Micky will cover 1400ft²

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