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zhannawk [14.2K]
3 years ago
11

(

id="TexFormula1" title=" (\frac{2}{3} x^{-3} y^{4} z^{2})^{3} " alt=" (\frac{2}{3} x^{-3} y^{4} z^{2})^{3} " align="absmiddle" class="latex-formula"> 
Mathematics
1 answer:
kobusy [5.1K]3 years ago
7 0
\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------

\bf \left(\cfrac{2}{3}x^{-3}y^4z^2  \right)^3\implies \stackrel{\textit{distributing the exponent}}{\left[\left( \cfrac{2}{3} \right)^3x^{^{-3\cdot 3}}y^{4\cdot 3}z^{2\cdot 3}  \right]}\implies \cfrac{2^3}{3^3}x^{-9}y^{12}z^6
\\\\\\
\cfrac{8}{27}\cdot \cfrac{1}{x^9}y^{12}z^6\implies \cfrac{8y^{12}z^6}{27x^9}
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Answer:

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Step-by-step explanation:

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