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2 years ago

(20 points!) (photo attached for context) Line segment ST is congruent to which line segment?

Mathematics

1 answer:

Brrunno [24]2 years ago

6 0

Opposites seem to me congruent in the image so reflect that across.
Line ST is congruent to UT

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Write an expression that represents the sum of a number x and 11

Helen [10]

Answer:

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2 years ago

The shopping center in Montgomeryville has 23,619 square feet the shopping center in harleyville has 6,522 square feet. What sta

Harman [31]

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3 years ago

Jack and Jim went biking. Jack biked for 5 1/3 hours with average speed 12 1/2 miles per hour. Jim traveled exactly 1 1/5 as far

ahrayia [7]

Given that Jack biked for $5 \frac{1}{3}$ hours with an average speed of $12 \frac{1}{2}$ miles per hour.

The distance travelled by Jack is given by

$d=speed\times time \\ \\ =12 \frac{1}{2}\times5 \frac{1}{3}= \frac{25}{2} \times \frac{16}{3} \\ \\ = \frac{200}{3} =66 \frac{2}{3} \ miles$

Given that Jim travelled exactly $1 \frac{1}{5}$ as far as Jack did, then the distance Jim travelled is given by

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3 0

2 years ago

Formulate the indicated conclusion in nontechnical terms. Be sure to address the original claim.

Art [367]

Answer:

The claim made by the motor company was true. The old sedan, the Libra, would average less than 19 miles per gallon in the city.

Step-by-step explanation:

In this case we need to test the claim made by the Carter Motor Company, that their old sedan, the Libra, would average less than 19 miles per gallon in the city.

The hypothesis to test the claim is as follows:

H₀: The old sedan, the Libra, would average not less than 19 miles per gallon in the city, i.e. μ ≥ 19.

Hₐ: The old sedan, the Libra, would average less than 19 miles per gallon in the city, i.e. μ < 19.

It is provided that the conclusion is to reject the null hypothesis.

This implies that, it was concluded that the old sedan, the Libra, would average less than 19 miles per gallon in the city.

Hence, the claim made by the motor company was true.

7 0

3 years ago

What number must be placed in the box in the equation below to produce an equation that has more than one solution: 5u+3(4u-6)=-

Sergeeva-Olga [200]

Answer: the number must be placed in the box is 9

suppose: the number must be placed in the box is x

have:

5u + 3(4u - 6) = -3u -27 + 20u + x

⇔ 5u + 12u - 18 = -3u - 27 + 20u +x

⇔ 17u + 3u - 20u = -27 + 18 + x

⇔ 0 = x - 9

⇔ x = 9

Step-by-step explanation:

7 0

3 years ago