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3 years ago

9

Joe throws a coin in the air. The height of the coin, in feet, can be modeled by the following function, where t is the number o

f seconds since the coin is thrown.
h(t) = -(t - 4)2 + 18

What is the maximum height of the coin?

1 answer:

Alla [95]3 years ago

5 0

I was told 7 feet idk if its correct

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What is the following simplified product? Assume x greater-than-or-equal-to 0 2 StartRoot 8 x cubed EndRoot (3 StartRoot 10 x Su

RideAnS [48]

This is the simplest form $4\sqrt{5}x^3(6\sqrt{x} -\sqrt{2})$ .

<h2>Exponent</h2>

Exponential notation is the form of mathematical shorthand which allows us to write complicated expressions more succinctly. An exponent is a number or letter is called the base. It indicates that the base is to raise to a certain power. X is the base and n is the power.

<h3>Simplification</h3>

Simplification is to make something easier to do or understand and to make something less complicated.

Given

$\rm 2\sqrt{8x^3} * (3\sqrt{10x^4} - x\sqrt{5x^2} )$ is an expression.

<h3>How to make it simple?</h3>

$\rm 2\sqrt{8x^3} * (3\sqrt{10x^4} - x\sqrt{5x^2} )$

On simplifying, we have

$\rm 4\sqrt{2} (x)^{\frac{3}{2}} * ( 3\sqrt{10} x^2 - \sqrt{5} x^{\frac{3}{2}})\\\\24\sqrt{5} x^{\frac{7}{2}} - 4\sqrt{10}x^3\\\\4\sqrt{5}x^3(6\sqrt{x} -\sqrt{2} )\\$

This is the simplest form $4\sqrt{5}x^3(6\sqrt{x} -\sqrt{2})$ .

More about the exponent link is given below.

brainly.com/question/5497425

7 0

2 years ago

Can anyone answer this?

Alona [7]

Answer:

Because the triangle is isosceles, the base angles are congruent. Since the sum of angles in a triangle is 180° we can write:

24 + x + x = 180

24 + 2x = 180

2x = 156

x = 78°

8 0

3 years ago

Read 2 more answers

URGENT!!!!<br> Please add workings out

Artist 52 [7]

Answer: 26.457 cm

Explanation:

First, the height of an equilateral triangle of side length a is:

$h = \frac{\sqrt{3} }{2}*a$

In this case, the side-length of the triangles is a = 10cm, then the height will be:

$h = \frac{\sqrt{3} }{2}*10cm = 8.66cm$

Now we can think on a triangle rectangle such that:

Point A and point F are vertexes of the triangle.

The line we want to find, the line from A to F, is the hypotenuse.

One cathetus is a the height of the triangle, that comes down from point A, the length of this cathetus is 8.66cm

The other cathetus is equal to half the side length of the triangles (5cm) plus the segments BD and DF (of 10cm each)

Then the length of this cathetus is 10cm + 10cm + 5cm = 25cm

Now, we can remember the Pythagorean theorem.

If H is the hypotenuse, and A and B are the catheti, then we have:

A^2 + B^2 = H^2

In this case, we know the length of both cathetus, and want to know the length of the hypotenuse, then:

(25cm)^2 + (8.66cm)^2 = H^2

√( (25cm)^2 + (8.66cm)^2) = H = 26.457 cm

Then the line from A to F is 26.457 cm

6 0

3 years ago

Help as soon as possible thanks

frutty [35]

6x11=66ft
3x14=42ft

Add the answers together
42+66
= 108 squared feet

5 0

2 years ago

Simplify.<br> 5 +8 X 2 – 10

sveticcg [70]

Answer:

-104

Step-by-step explanation:

5+8=13

2-10=-8

13×-8=-104

4 0

3 years ago