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kicyunya [14]
2 years ago
9

Joe throws a coin in the air. The height of the coin, in feet, can be modeled by the following function, where t is the number o

f seconds since the coin is thrown.
h(t) = -(t - 4)2 + 18

What is the maximum height of the coin?
Mathematics
1 answer:
Alla [95]2 years ago
5 0
I was told 7 feet idk if its correct
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4(2x-3)=0.2(x+5)÷5.72
rusak2 [61]

Answer:

x=1.528534

Explanation:

Simplify both sides of equation

4(2x-3)=0.2(x+5)/5.72

(4)(2x)+(4)(−3)=0.034965x+0.174825(Distribute)

8x+−12=0.034965x+0.174825

8x−12=0.034965x+0.174825

Step 2: Subtract 0.034965x from both sides.

8x−12−0.034965x=0.034965x+0.174825−0.034965x

7.965035x−12=0.174825

Step 3: Add 12 to both sides.

7.965035x−12+12=0.174825+12

7.965035x=12.174825

Step 4: Divide both sides by 7.965035.

7.965035x/7.965035=12.174825/7.965035

x=1.528534

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