50 minutes= 5/6 hr
(1 3/4 miles)/ (5/6 hr)= 2.1 miles/hr
Hope this would help~



with that template in mind, let's see,

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.
the smaller A is, the wider it opens, the larger it is, the more it shrinks.
A = L * W
W = L - 5
these are in inches...
length width area
10 5 50 in^2
9 4 36 "
8 3 24 "
7 2 14 "
6 1 6 "
Answer:
yea by using a resipe
Step-by-step explanation:
<h3>
Answer:</h3>
- B. f(x) = 3,000(0.85)^x
- $1566.02
<h3>
Step-by-step explanation:</h3>
Part A
At the end of the year, the value of the computer system is ...
... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)
... = 0.85 · (beginning value)
Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...
... f(x) = (beginning value) · 0.85^x
The beginning value is given as $3000, so this is ...
... f(x) = 3000·0.85^x
____
Part B
For x=4, this is ...
... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02
The value after 4 years is $1566.02.