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zhannawk [14.2K]
3 years ago
13

How to graph 2x-y=3

Mathematics
2 answers:
WINSTONCH [101]3 years ago
5 0
First you would need to convert the equation to match the y = mx + b format. 

Subtract 2x from both sides to get -y = -2x + 3 

Then, divide -1 (because that's the coefficient to -y, on all values, turning to equation into 
y = 2x - 3 (negative and negative makes a positive that's why the 2 value is now positive) in order to make the y value positive.

Our y intercept is -3 so start your graphing line on the -3 value on the x axis. 

Our slope is 2/1 which means to go up 2 point and right 1 point, since it's a positive slope.

You can mark every point in order to get a more accurate line and just connect the dots from there. Be sure to use a ruler or some sort of straightedge for a better line.

Hope this helped :)
11Alexandr11 [23.1K]3 years ago
4 0
Fotofotofotofotofotofotofotofotofotofoto

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4 0
3 years ago
Pre cal/cal master needed
weqwewe [10]
Take x-2 and insert it into 2x^2 + 3x-2 where the x is located 
2x^2 + 3x-2
2(x-2)^2 + 3(x-2)-2

Now work out 2(x-2)^2 + 3(x-2)-2 also follow PEMDAS
2(x-2)^2 + 3(x-2)-2 
Since (x-2)^2 is an Exponent, lets work with that first and expand (x-2)^2.
(x-2)^2
(x -2)(x-2)
x^2 -4x + 4
Now Multiply that by 2 because we have that in 2(x-2)^2
(x-2)^2  =  x^2 -4x + 4
2(x-2)^2  =  2(x^2 -4x + 4)
2(x^2 -4x + 4) = 2x^2 - 8x + 8
2x^2 - 8x + 8

Now that 2(x-2)^2 is done lets move on to 3(x-2).

Use the distributive property and distribute the 3
3(x-2) = 3x - 6

All that is left is the -2 

Now lets put it all together 
2(x-2)^2 + 3(x-2)-2

2x^2 - 8x + 8 + 3x - 6 - 2

Now combine all our like terms 
2x^2 - 8x + 8 + 3x - 6 - 2
Combine:  2x^2      =  2x^2 
Combine: -8x + 3x  =  -5x
Combine:  8 - 6 - 2 =   0

So all we have left is
2x^2 - 5x





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Step-by-step explanation:

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