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nadya68 [22]
3 years ago
15

There are 4 red golf balls and 2 green golf balls in a bucket. You select a ball at random, keep it, and select again. Find the

probability.
P(both red)

A. 1/3


B. 4/9


C. 2/3


D. 2/5
Mathematics
2 answers:
Alona [7]3 years ago
6 0

Answer:

C

Step-by-step explanation:

It should be 2/3 because there are 6 balls and two of them are green which gives the fraction 2/6 and can be reduced to 1/3

just olya [345]3 years ago
4 0

Answer:

P(both red)=C

Step-by-step explanation:

There are 6 golf balls in total and 4 golf balls is half of it. There is a 2/3 chance that you will get red balls. When you select again, the chances are the same so the probability can be simplified again back to 2/3.

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A cylinder has a height of 4 meters and a diameter that is 12 meters. Using 3.14 for pi, which of the following can be used to c
Studentka2010 [4]

Answer:

Step-by-step explanation:

h = 4 m

d =  12 m

r = 12/2 = 6 m

Volume of cylinder = πr²h

                               = 3.14 * 6 * 6 * 4

                               = 452.16 m³

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3 years ago
Round this number to the nearest 10,000.<br> 64,195<br> A. 70,000<br> B. 50,000<br> C. 60,000
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The answer is C. 60,000
7 0
3 years ago
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svetlana [45]
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4 0
3 years ago
Read 2 more answers
Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i
Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let <em>X</em> = <em>r</em><em> </em>= a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = <em>p</em> = 0.35.

The sample selected is of size <em>n</em> = 12.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 12 and <em>p</em> = 0.35.

The probability function of a binomial random variable is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x}

(a)

For <em>X</em> = 0 the probability is:

P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006

For <em>X</em> = 1 the probability is:

P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037

For <em>X</em> = 2 the probability is:

P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

E(X)=np

The expected number of vehicles out of 12 that will tailgate is:

E(X)=np=12\times0.35=4.2

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

SD(X)=np(1-p)

The standard deviation of vehicles out of 12 that will tailgate is:

SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

4 0
3 years ago
What is the solution to f(-2)=-|-2-2|
nexus9112 [7]

Answer:

f = -4

Explanation:

  • f(-2) = -|-2 - 2|

Subtract The Numbers: -2 - 2 = 4

f = -| -4|

Apply Absolute Rule (|-a| = a): |-4| = 4

f = -4

3 0
3 years ago
Read 2 more answers
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