Answer:
201
Step-by-step explanation:
The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
x-axis is y=0, so the answer is D.
but not D. Luffy
Answer:
c
Step-by-step explanation:
x*x=x^2
x*9=9x
x*3=3x
9x+3x=12x
9x3=27
x^2+12x+27
A dilation is a transformation, with center O and a scale factor of k
that is not zero, that maps O to itself and any other point P to P'.
The center O is a fixed point, P' is the image of P, points O, P and P'
are on the same line.
Thus, a dilation with centre O and a scale factor of k maps the original figure to the image in such a way that the<span>
distances from O to the vertices of the image are k times the distances
from O to the original figure. Also the size of the image are k times the
size of the original figure.
In the dilation of triangle TUV</span>, It is obvious that the image <span>T'U'V' is smaller than the original triangle TUV and hence the scale factor is less than 1.
</span>The ratio of the
distances from A to the vertices of the image T'U'V' to the distances
from A to the original triangle TUV is the scale factor.
The scale factor = 3.2 / 4.8 = 2/3
