P(at least 5 rolls until 1) = P(4 rolls are not 1) = 5/6 x 5/6 x 5/6 x 5/6 = 0.4823 (4sf)
Fewer than 7 rolls to get second 1 after first takes 3 rolls means second occurs on 4th, 5th or 6th roll
The probability of each of these is 1/6, 5/6 x 1/6 and 5/6 x 5/6 x 1/6 respectively.
P(second 1 on 4th, 5th or 6th roll) = 1/6 + 5/36 + 25/216 = 91/216 = 0.4213 (4sf)
Answer:
As eq of line passing through 2 points is
y-y1 = (y2-y1)/(x2-x1) ][ x -x1)
where (X1,y1)( x2, y2) denotes points lying on line
substitute (X1 ,y1) by( -1,-2) and (X2,y2) by( 2,4)
y+2 = 6/3 )( x+1)
y+2= 2x +2
y = 2x is required equation
Answer:
Step-by-step explanation:
4
Answer:
2/3
Step-by-step explanation:
16/24 = 14/ 21 = 12/ 18 10/ 15 8/12 6/9 4/6 = 2/3
