Answer:
Step-by-step explanation:
The horizontal leg is 0, since there is no horizontal component of the triangle, so, the cosine is 0. Consider the angle itself and the unit circle. There is no horizontal component of the angle: The horizontal component of the angle is 0, so, the cosine of 90° is 0.
Answer:The solution is in the attached file
Step-by-step explanation:
![log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x](https://tex.z-dn.net/?f=log_b%7B162%7D%20%3D%20x%20%2B%204y%5C%5C%5C%5Clog_b324%20%3D%202x%2B4y%5C%5C%5C%5Clog_b%5Cfrac%7B8%7D%7B9%7D%20%3D%203x-2y%5C%5C%5C%5C%5Cfrac%7Blog_b27%7D%7Blog_b16%7D%20%3D%203y-4x)
<em><u>Solution:</u></em>
Given that,
![log_b2 = x\\\\log_b3 = y --------(i)](https://tex.z-dn.net/?f=log_b2%20%3D%20x%5C%5C%5C%5Clog_b3%20%3D%20y%20--------%28i%29)
<em><u>Use the following log rules</u></em>
Rule 1: ![log_b(ac) = log_ba + log_bc](https://tex.z-dn.net/?f=log_b%28ac%29%20%3D%20log_ba%20%2B%20log_bc)
Rule 2: ![log_b\frac{a}{c} = log_ba - log_bc](https://tex.z-dn.net/?f=log_b%5Cfrac%7Ba%7D%7Bc%7D%20%3D%20log_ba%20-%20log_bc)
Rule 3: ![log_ba^c = clog_ba](https://tex.z-dn.net/?f=log_ba%5Ec%20%3D%20clog_ba)
![a) log_b{162}](https://tex.z-dn.net/?f=a%29%20log_b%7B162%7D)
Break 162 down to primes:
![162 = 2^1 \times 3^4](https://tex.z-dn.net/?f=162%20%3D%202%5E1%20%5Ctimes%203%5E4)
![log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y](https://tex.z-dn.net/?f=log_b%7B162%7D%20%3Dlog_b%202%5E1.%203%5E4%5C%5C%5C%5CBy%5C%20rule%5C%201%5C%5C%5C%5C%20log_b%7B162%7D%20%3D%20log_b%202%5E1%20%2Blog_b%203%5E4%5C%5C%5C%5CBy%5C%20rule%5C%203%5C%5C%5C%5C1log_b2%20%2B%204log_b3%5C%5C%5C%5C1x%2B4y%5C%5C%5C%5Cx%2B4y)
Thus we get,
![log_b162 = x + 4y](https://tex.z-dn.net/?f=log_b162%20%3D%20x%20%2B%204y)
Next
![b) log_b 324](https://tex.z-dn.net/?f=b%29%20log_b%20324)
Break 324 down to primes:
![324 = 2^2 \times 3^4](https://tex.z-dn.net/?f=324%20%3D%202%5E2%20%5Ctimes%203%5E4)
![log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y](https://tex.z-dn.net/?f=log_b324%20%3D%20log_b%202%5E2.3%5E4%5C%5C%5C%5CBy%5C%20rule%5C%201%5C%5C%5C%5Clog_b324%20%3D%20log_b2%5E2%20%2B%20log_b3%5E4%5C%5C%5C%5CBy%5C%20rule%5C%203%5C%5C%5C%5Clog_b324%20%3D%202log_b2%20%2B%204log_b3%5C%5C%5C%5CFrom%5C%20%28i%29%5C%5C%5C%5Clog_b324%20%3D%202x%20%2B%204y)
Next
![c) log_b\frac{8}{9}](https://tex.z-dn.net/?f=c%29%20log_b%5Cfrac%7B8%7D%7B9%7D)
By rule 2
![log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y](https://tex.z-dn.net/?f=log_b%5Cfrac%7B8%7D%7B9%7D%20%3D%20log_b8%20-%20log_b9%5C%5C%5C%5Clog_b%5Cfrac%7B8%7D%7B9%7D%20%3D%20log_b%202%5E3%20-%20log_b3%5E2%5C%5C%5C%5CBy%5C%20rule%5C%203%5C%5C%5C%5Clog_b%5Cfrac%7B8%7D%7B9%7D%20%3D%20%203%20log_b2%20-%202log_b3%5C%5C%5C%5CFrom%5C%20%28i%29%5C%5C%5C%5Clog_b%5Cfrac%7B8%7D%7B9%7D%20%3D%20%203x%20-%202y)
Next
![d) \frac{log_b27}{log_b16}](https://tex.z-dn.net/?f=d%29%20%5Cfrac%7Blog_b27%7D%7Blog_b16%7D)
By rule 2
![\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x](https://tex.z-dn.net/?f=%5Cfrac%7Blog_b27%7D%7Blog_b16%7D%20%3D%20log_b27%20-%20log_b16%5C%5C%5C%5C%20%5Cfrac%7Blog_b27%7D%7Blog_b16%7D%20%3D%20log_b3%5E3%20-%20log_b2%5E4%5C%5C%5C%5CBy%5C%20rule%5C%202%5C%5C%5C%5C%20%5Cfrac%7Blog_b27%7D%7Blog_b16%7D%20%3D%203log_b3%20-%204log_b2%20%5C%5C%5C%5CFrom%5C%20%28i%29%5C%5C%5C%5C%5Cfrac%7Blog_b27%7D%7Blog_b16%7D%20%3D%20%203y%20-%204x)
Thus the given are evaluated in terms of x and y
Plug in the values of p and q where you see them in the equation:
-(2+4)2 / (-6) - Distribute the -1
(-2-4)2 / (-6) - Distribute the 2
(-4-8) / (-6) - Subtract what's inside the parenthesis
(-12) / (-6) - Divide
The answer is 2
Should be 1204.75? use this answer to check your work!
My work:
14 times 18 (since there’s two triangles) = 252
36 times 28 = 1008
6.5 times 8.5 = 55.25
(1008 + 252) - 55.25 = 1204.75