Answer:
2) 65
3) -6
4) -15
5) -6
Step-by-step explanation:
Answer:
1) 1.8
2) 1.7
Step-by-step explanation:
(for part A)
Mean: 3 + 5 + 6 + 3 + 2 + 2 + 1 + 0 + 0 + 4 + 7 + 4 + 5 + 5 + 6 = 53/15 = 3.5
3.5 - 3 = 0.5
3.5 - 5 = 1.5
3.5 - 6 = 2.5
3.5 - 3 = 0.5
3.5 - 2 = 1.5
3.5 - 2 = 1.5
3.5 - 1 = 2.5
3.5 - 0 = 3.5
3.5 - 0 = 3.5
3.5 - 4 = 0.5
3.5 - 7 = 3.5
3.5 - 4 = 0.5
3.5 - 5 = 1.5
3.5 - 5 = 1.5
3.5 - 6 = 2.5
mean absolute deviation: 0.5 + 1.5 + 2.5 + 0.5 + 1.5 + 1.5 + 2.5 + 3.5 + 3.5 + 0.5 + 3.5 + 0.5 + 1.5 + 1.5 + 2.5 = 27.5/15 = 1.8
(part B)
Mean: -3 + -2 + -1 + 0 + 1 + 2 + 3 = 0/7 = 0
0 - (-3) = 3
0 - (-2) = 2
0 - (-1) = 1
0 - 0 = 0
0 - 1 = 1
0 - 2 = 2
0 - 3 = 3
mean absolute deviation: 3 + 2 + 1 + 0 + 1 + 2 + 3 = 12/7 = 1.7
I started this and got distracted and never finished and it timed out. Focus Dean.
It's not the best graph; I assume the origin is the apparent origin and the y axis numbers go with the line above them.
This graph is M(V), M(V) is mass in kg of bucket with water volume V in liters
a) the mass of an empty bucket
That's the y intercept, M(0), eyeballing it around .7 kg
Answer: .7 kg
b) the mass of the bucket containing 1 liter of liquid
That's M(1), looks like 1.3 or so
Answer: 1.3 kg
c) the mass of one liter of liquid
That's the difference, M(1)-M(0), about .6 kg. We can get a better estimate from a longer slope, say (.5,1) to (3,3), (3-1)/(3-.5) = .8 kg.
Answer
: 0.8 kg
d) the volume of the liquid in the bucket, if the total mass of bucket with the liquid is 3 kg.
Solve M(V)=3
That has a solution from the graph V=3.
Answer: 3 liters
Area enclosed in 
radians =$\pi r^2$
so area enclosed in $\theta$ radians=$\theta \times \frac{\pi r^2}{2\pi}= \frac{1}2\theta r^2$
does this answer your question?
