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DedPeter [7]
3 years ago
8

Classify each real number. List all the subsets in which the number belongs.

Mathematics
1 answer:
kolbaska11 [484]3 years ago
8 0

Answer:

Step-by-step explanation:

1-integer

2-rational

3-whole

4- irrational

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How do you solve this equation 5b-0.7=6b
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Answer:

Subtract 5b from both sides of the equation

-0.7 = 1b

Get B value alone so divide 1 on both sides of the equation

B = -0.7

Step-by-step explanation:

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Claudia is making a gelatin dessert for a party. She plans on making 12 servings for every 5 people. If each pan Claudia uses to
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Answer:

3

Step-by-step explanation:

Key Word: 12 servings for every 5 people. if she makes it to hold 8 servings, what is enough plans she needs to feed 10 people?

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solving problem:

12 people over 5 people = x over 10 people

since 5 times 2 equals 10 then 12 times is 24.. so we need 24 servings

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ANSWER : 3

6 0
3 years ago
One way to find a common denominator is by
Lena [83]

Answer:

Step-by-step explanation:

a). 1\frac{3}{5}=1+\frac{3}{5}

         =1+\frac{3}{5}\times \frac{4}{4}

         =1+\frac{12}{20}

         =1\frac{12}{20}

   1\frac{3}{4}=1+\frac{3}{4}

        =1+\frac{3}{4}\times \frac{5}{5}

        =1+\frac{15}{20}

        =1\frac{15}{20}

Therefore, common denominator of 20.

b). 2\frac{1}{2}=2+\frac{1}{2}

         =2+\frac{1}{2}\times \frac{5}{5}

         =2+\frac{5}{10}

         =2\frac{5}{10}

     \frac{4}{5}=\frac{4}{5}\times \frac{2}{2}

        =\frac{8}{10}

Common denominator of 10.

c). \frac{3}{8}=\frac{3}{8}\times \frac{6}{6}

       = \frac{18}{48}

   \frac{1}{6}=\frac{1}{6}\times \frac{8}{8}

      = \frac{8}{48}

Common denominator of 48.

3 0
3 years ago
suppose that n is a positive integer written in base 10. prove that n is divisible by 3 if and only if the sum of its decimal di
Goshia [24]

Modulo - The result of multiplying the original number by three and the result of multiplying the digits by three must be the same.

What is modulo?

In mathematics, the phrase modulo, which literally means "with respect to a modulus of," is frequently used to claim that two different mathematical objects can be regarded as comparable if their difference is explained by a third component.

Using the Fermat's little theorem:

x^n-1 =(x-1)(x^{n-1}+x^{n-2}+....+x+1)

when x=10. You may easily establish the identity by multiplying it term by word. All terms cancel, excluding the first and last ones. Therefore, any power of ten minus one is divisible by nine, and consequently, by three

Now consider a multi-digit natural number, 43617 for example.

43617= 4*10^4+3*10^3+6*10^2+1*10+7

= 4*9999+3*999+6*99+1*9+(4+3+6+1+7)

Other than the sum of the digits, every term on the right is divisible by 3. The result of multiplying the original number by three and the result of multiplying the digits by three must be the same.

to learn more about exponents and power visit:

brainly.com/question/19120853

#SPJ4

5 0
2 years ago
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