Answer:
all boxes except first should be checked
Step-by-step explanation:
the shaded area contains all solutions
see if each ordered pair resides in the solution area
<h3>
Answers:</h3><h3>x = sqrt(10)</h3><h3>y = sqrt(5)</h3>
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Explanation:
Naturally I start with x as that letter precedes y in the alphabet; however, it's easier to start with y because it is a leg of this triangle. We will then use the value of y to find x later.
For any 45-45-90 triangle, the two legs are the same length. So that's why we're able to quickly see that y = sqrt(5)
To get the hypotenuse, we multiply the leg length by sqrt(2). This trick only works for 45-45-90 triangles.
hypotenuse = leg*sqrt(2)
x = sqrt(5)*sqrt(2)
x = sqrt(5*2)
x = sqrt(10)
The rule I used is sqrt(a)*sqrt(b) = sqrt(a*b)
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An alternate path is to use the pythagorean theorem to find x
a^2+b^2 = c^2
(sqrt(5))^2 + (sqrt(5))^2 = x^2
5 + 5 = x^2
10 = x^2
x^2 = 10
x = sqrt(10)
In order to determine which subset it belongs, we must rewrite
as
All these three numbers are irrational numbers, hence their product is also irrational
<h2>
</h2><h2>belongs to the set of
irrational numbers</h2>
Answer:
Slope is -2
Step-by-step explanation:
(y2-y1) / (x2-x1)
(6-10) / (-10+12) = (-4)/(2) = <u>-2</u>
Answer:
CI=[0.8592,0.9402]
Yes, Method appears to be effective.
Step-by-step explanation:
-We first calculate the proportion of girls born:
Since np
, we assume normal distribution and calculate the 99% confidence interval as below:
![CI=\hat p\pm z\sqrt{\frac{\hat p(1-\hat p)}{n}}\\\\=0.9\pm2.576\sqrt{\frac{0.9\times 0.1}{370}}\\\\=0.9\pm 0.0402\\\\={0.8598, \ 0.9402]](https://tex.z-dn.net/?f=CI%3D%5Chat%20p%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D%5C%5C%5C%5C%3D0.9%5Cpm2.576%5Csqrt%7B%5Cfrac%7B0.9%5Ctimes%200.1%7D%7B370%7D%7D%5C%5C%5C%5C%3D0.9%5Cpm%200.0402%5C%5C%5C%5C%3D%7B0.8598%2C%20%5C%200.9402%5D)
Hence, the confidence interval is {0.8598, 0.9402]
-The probability of giving birth to a girl is 0.5 which is less than the lower boundary of the confidence interval, it can be concluded that the method appears to be effective.
