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erastova [34]
2 years ago
10

Evaluate if a=4&b= 7 10 + (b − a) • 5 ​

Mathematics
1 answer:
Margarita [4]2 years ago
6 0
ANSWER= 25



a= 4 b=7

10+(7-4)•5

subtract 7-4= 3

10+3•5

multiply 3•5=15

10+15

add them and your answer is 25

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Find the sum of the following geometric series.<br><br> 8 + 1.6 + 0.32 + 0.064 +...
bazaltina [42]
Answer is : 1.2 geometric series
4 0
2 years ago
Evaluate the expression for p=2<br> 81-p
Burka [1]
P=2 so 81-p is equal to 81-2 which equals 79
7 0
3 years ago
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2x + 5 =12<br> What is x
lisabon 2012 [21]

Answer:

7/2

Step-by-step explanation:

2x=12-5....collectible like terms

2x=7

x=7/2...dividing both side by 2

3 0
3 years ago
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Find the smallest 4 digit number such that when divided by 35, 42 or 63 remainder is always 5
alex41 [277]

The smallest such number is 1055.

We want to find x such that

\begin{cases}x\equiv5\pmod{35}\\x\equiv5\pmod{42}\\x\equiv5\pmod{63}\end{cases}

The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.

x\equiv5\pmod{35}\implies\begin{cases}x\equiv5\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{42}\implies\begin{cases}x\equiv5\equiv1\pmod2\\x\equiv5\equiv2\pmod3\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{63}\implies\begin{cases}x\equiv5\equiv2\pmod 3\\x\equiv5\pmod7\end{cases}

Taking everything together, we end up with the system

\begin{cases}x\equiv1\pmod2\\x\equiv2\pmod3\\x\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

Now the moduli are coprime and we can apply the CRT.

We start with

x=3\cdot5\cdot7+2\cdot5\cdot7+2\cdot3\cdot7+2\cdot3\cdot5

Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.

Taken modulo 2, we end up with

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod2

which means the first term is fine and doesn't require adjustment.

Taken modulo 3, we have

x\equiv2\cdot5\cdot7\equiv70\equiv1\pmod3

We want a remainder of 2, so we just need to multiply the second term by 2.

Taken modulo 5, we have

x\equiv2\cdot3\cdot7\equiv42\equiv2\pmod5

We want a remainder of 0, so we can just multiply this term by 0.

Taken modulo 7, we have

x\equiv2\cdot3\cdot5\equiv30\equiv2\pmod7

We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since 2\cdot4\equiv8\equiv1\pmod7, the inverse of 2 is 4.

So, we have to adjust x to

x=3\cdot5\cdot7+2^2\cdot5\cdot7+0+2^3\cdot3\cdot5^2=845

and from the CRT we find

x\equiv845\pmod2\cdot3\cdot5\cdot7\implies x\equiv5\pmod{210}

so that the general solution x=210n+5 for all integers n.

We want a 4 digit solution, so we want

210n+5\ge1000\implies210n\ge995\implies n\ge\dfrac{995}{210}\approx4.7\implies n=5

which gives x=210\cdot5+5=1055.

5 0
3 years ago
Angle θ is in standard position. if sin(θ) = − 1 3 , and π &lt; θ &lt; 3π 2 , find cos(θ).
kramer

The value of the angle θ is 160.52° then the value of the cosine will be negative 0.9428.

<h3>What is trigonometry?</h3>

Trigonometry deals with the relationship between the sides and angles of a right-angle triangle.

Angle θ is in standard position.

If sin(θ) = − 1/3 , and π < θ < 3π/2

Then the angle will be

\theta = \sin ^{-1}\dfrac{-1}{3}\\\\\theta = -19.47

Then add 180 degrees, then we have

\theta = -19.47 + 180\\\\\theta = 160.52

Then the value of the cosine will be

\cos 160.52^o=-0.9428

More about the trigonometry link is given below.

brainly.com/question/22698523

7 0
2 years ago
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