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Sergeeva-Olga [200]
3 years ago
9

Factor the expression using the GCF. 7+14

Mathematics
1 answer:
Deffense [45]3 years ago
7 0
Factors of 7: 1 and 7
Factors of 14: 1, 2, 7, and 14
ANSWER IS GCF: 7
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Determine which of the following are functions. Select all that apply.
Firlakuza [10]

Answer:

I am led to believe the answers are 4 and 1

Step-by-step explanation:

I don't think its answer 2 because thou are radios and their isn't any fractions in it

I solved answer 4 it came as a fraction

Okay i looked at 1 and i did all of them they all came out as a decimal so i think that's another one

answer 3 you can't divide by 0 so i don't think so

8 0
3 years ago
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I need help, please​
tensa zangetsu [6.8K]

Answer:

C

Step-by-step explanation:

12^2 = 144, 9^2 = 81, and 15^2 = 225.

144 + 81 = 225, therefore a^2 + b^2 = c^2.

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3 years ago
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(08.03)
Alik [6]

Answer:

Option D, (x + 2)(x - 6)

Step-by-step explanation:

<u>Step 1:  Factor </u>

x^2 - 4x - 12

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(x - 6)(x + 2)

(x + 2)(x - 6)

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8 0
3 years ago
A flying carpet flies 2.4 miles with the wind in the same amount of time it flies 1.4 miles against the wind. The wind speed is
Ainat [17]

Answer:

15.2~mph

Step-by-step explanation:

Let the time flown by the flying carpet be t. Then, we have that (2.4)/t=(1.4)/t+2*4.

We multiply both sides of the equation by t to get 2.4=1.4+8t.

We subtract 1.4 from both sides to get 1=8t.

We divide both sides of the equation by t=1/8.

We know that the speed of the flying carpet in still wind is the average of the rates of the speed of the flying carpet with the wind and against the wind.

The speed with wind is (2.4)/(1/8)=19.2mph.

The speed against wind is (1.4)/(1/8)=11.2mph.

The speed in still wind is (19.2+11.2)/2=(30.4)/2=15.2.

Therefore, the answer is \boxed{15.2~mph} and we're done!

4 0
3 years ago
Which equation represents the graph?
frosja888 [35]

Answer:

The answer is A) y+4 =3(x+3)

Step-by-step explanation:

The slope is the rate of change, which you can see from the graph is m = 3/1 = 3.

Your options are given in point-slope form:

y-y1=m(x-x1)

Pick a point from the graph. I used;

(-3, -4). Now plug this into your point slope form equation.

y-(-4) = 3(x-(-3))

y+4=3(x+3)

8 0
3 years ago
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