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tia_tia [17]
2 years ago
7

How many fluid ounces are in 3 1/4 cups?

Mathematics
2 answers:
Andre45 [30]2 years ago
7 0

Answer: The Answer is 26

Step-by-step explanation: Well, I first divided 3 by 4 and then I got 1 and then I did 1 + 23 and got 24 and then 3 made even is 2 so I added 2 and got 26!

tresset_1 [31]2 years ago
7 0

Answer:

26

Step-by-step explanation:

I don't know if this is right but im fairly certain it is.

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The growth of a group of bacteria is modeled by the function f(x) =10x. Identify the key features of the model.
Luden [163]
The Y INTERCEPT is x the range is 10
6 0
3 years ago
X(21)+x(4)=300 I need solving
Genrish500 [490]

Answer:

12

Step-by-step explanation:

21x + 4x = 300         Put brackets around the first two terms.

(21x + 4x) = 300        Pull the x outside the brackets. Use the distributive property.  Combine the left

25x = 300                 Divide by 25

25x/25=300/25        Do the division

x = 12

                 

5 0
4 years ago
I need help with this A=1/2 bh for b
NemiM [27]

A = 1/2 bh can be written as

A = bh/2.

2A = (bh/2)(2)

2A = bh

Divide both sides by h to find b.

2A/h = b

Done.

3 0
3 years ago
Read 2 more answers
Simplify 6/10 + 8.75?
PilotLPTM [1.2K]
First do 6 divided by 10

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4 years ago
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A polynomial with rational coefficients has roots 5 and -6i. (The i is an imaginary number not variable). What is the polynomial
mars1129 [50]

Answer:

<em>The answer is</em>  <em>{x^{3}-(5)x^{2} (36)× x-(180)</em>

Step-by-step explanation:

   A polynomial with rational coefficients has roots 5 and -6i (There i is the    

   imaginary number not variable )

   As we knew that imaginary no comes in pair . This means that if  -6i is

   one root then the other root will be 6i

   So if we assume the lowest polynomial that is possible is given as

    {x^{3}-(sum of all roots)x^{2} +(roots taken two at a time)

    x-(product of all roots)

    {x^{3}-(5+6i+(-6i))x^{2} +(5×6i +5×(-6i) +6i×(-6i))

    x-(5×6i×(-6i))

    i^2 = -1

    <em>{x^{3}-(5)x^{2} (36)× x-(180)</em>

<em>    </em>The <u>general case</u> we assume that the three previous roots and rest roots

   a4,a5,a6 ...............an

  x^n-(sum of all roots)×x^{n-1} +(roots taken two at a  

   time) ×x^{n-2}- .......................................... (product of all roots)

3 0
3 years ago
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