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Fuseina has ¢40000 to invest.She decides to put part of the money in an account paying 4% interest and the reminder into stocks
1 answer:
Answer:
The amounts invested in the account = ¢ 18000
and the amount invested in the stock = ¢40000-¢18000= ¢22000.
Step-by-step explanation:
Given that the account paying 4% interest and the stocks paying 6% interest.
Assuming she put ¢ x in the account, so
Income (interest) from the account = 4% of x = ¢ 0.04x...(i)
She has a total of ¢ 40000 to invest, so the remaining amount = ¢(40000-x).
As she put the remaining amount into stock, so
Income (interest) from the stock=6% of (40000-x)=¢(2400-0.06x)...(ii)
As total income from the investment is ¢ 2040, so on adding both the incomes from equations (i) and (ii), we have
So, the amount invested in the account = ¢ 18000
and the amount invested in the stock = ¢40000-¢18000= ¢22000.
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Answer:
Perry's claim is correct while Karina is incorrect
Step-by-step explanation:
Question is incomplete (See Attachment)
First, we need to determine the area covered by Karina and Perry
For Karina, there are 9 square boxes each of which has an area of 1 unit sq
So:
For Perry:
There are 18 square boxes, each of which has an area of 1 unit sq.
So:
Comparing both areas, we can conclude that <em>Perry's claim is correct while Karina is incorrect</em>
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