Answer:
91.125 or 729/8
Step-by-step explanation:
take 4.5^3 to get 91.125
Answer:
<h2>3.6°</h2>
Step-by-step explanation:
The question is incomplete. Here is the complete question.
Find the angle between the given vectors to the nearest tenth of a degree.
u = <8, 7>, v = <9, 7>
we will be using the formula below to calculate the angle between the two vectors;

is the angle between the two vectors.
u = 8i + 7j and v = 9i+7j
u*v = (8i + 7j )*(9i + 7j )
u*v = 8(9) + 7(7)
u*v = 72+49
u*v = 121
|u| = √8²+7²
|u| = √64+49
|u| = √113
|v| = √9²+7²
|v| = √81+49
|v| = √130
Substituting the values into the formula;
121= √113*√130 cos θ
cos θ = 121/121.20
cos θ = 0.998
θ = cos⁻¹0.998
θ = 3.6° (to nearest tenth)
Hence, the angle between the given vectors is 3.6°
Answer:
third one
Step-by-step explanation:
2g+2>-4
g>-3
Answer:
D
Step-by-step explanation:
since it's a multiplication consider the two factors one by one
cubic root of y^6 = y^(6/3) = y^2
cubic root of 8x^3= 2x^(3/3)= 2x
so 2xy^2
-6 1/3 because it looks less than -6.375 which would mean that it is in fact bigger on the number scale.