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Aleksandr-060686 [28]
3 years ago
7

Help ahahha help nsnakkksams zbxjakaansndiakqmwjkwkdxm

Mathematics
2 answers:
aksik [14]3 years ago
7 0

Answer:B

Step-by-step explanation:

Bingel [31]3 years ago
5 0

Answer:

correct answer is b!!!!

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Grace starts with 100 milligrams of a radioactive substance. The amount of the
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100 is grace's initial amount. w is how much of the substance is being decrased each week. in ryan's equation, 1 is 100% of the substance, so the initial amount, and 0.4 is the amount that is being decreased.

Step-by-step explanation:

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4 years ago
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Зn + 14 = -4<br> What’s the n
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3 years ago
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What’s is the answer
kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

(x^{2} )^{3} = x^6

(x^{3} )^5=x^{15}


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3})=x^{5}

(x^{1} )(x^{2})=x^{3}


(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}

You multiply 3 into each exponent in the numerator and the denominator

\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}


When you have something like this:

\frac{x^{2}}{x^5}

You subtract the exponents together, so:

\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}


Your answer is the second option

3 0
3 years ago
Why is 3÷0.5 is 6, why is it?​
Alekssandra [29.7K]

Answer:

Step-by-step explanation:

A quick way to divide by 0.5 or ½ is to double the number (or multiply number by 2). The reason for this is that two halves go into a whole.

3 0
3 years ago
587,504 rounded to the nearest ten thousand is
Kobotan [32]
590,000

87,504 it closer to 90,000 that 80,000 so 587,504 rounded to the nearest ten thousand is 59,000
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3 years ago
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