B involves direct variation.
y and x are directly proportional.
Answer:
What is the question?
Step-by-step explanation:
prime: 1, 2, 3, 5
composite: 4, 6
Beto has 2/6 = 1/3 chance of winning
Amanda has 4/6 = 2/3 chance of winning
Answer:
g(2) = -42
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
<u>Algebra II</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em /><em />
<em />
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em> [Function g(n)]: g(2) = 8 - g(2 - 1)
- (Parenthesis) Subtract: g(2) = 8 - g(1)
- Substitute in function value: g(2) = 8 - 50
- Subtract: g(2) = -42
Answer:
5/2 x^2y^2
Step-by-step explanation:
( x^2 - 3/5y^2)^2 + (3/4 x^2 + 4/5 y^2)^2 - (5/4x^2 - y^2)^2
= x^4 - 6/5x^2y^2 + 9/25y^4 + 9/16x^4 + 6/5x^2y^2 + 16/25y^4 - ( 25/16x^4
- 5/2x^2y^2 + y^4)
Distributing the negative over the parentheses:-
= x^4 - 6/5x^2y^2 + 9/25y^4 + 9/16x^4 + 6/5x^2y^2 + 16/25y^4
- 25/16x^4
+ 5/2x^2y^2 - y^4
Bringing like terms together
x^4 + 9/16x^4 - 25/16x^4 - 6/5x^2y^2 + 6/5x^2y^2 + 5/2x^2y^2 + 16/25y^4 + 9/25y^4
- y^4
Adding like terms:-
= 5/2 x^2y^2 Answer
Answer:
a.is approximately normal because of the central limit theorem.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question:
Sample limit of 32 > 30, so the distribution is approximately normal because of the central limit theorem, and the correct answer is given by option a.