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3 years ago

HEEEEEEEEELP!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

EleoNora [17]3 years ago

8 0

Answer:

Look at the image.

Step-by-step explanation:

(36 ÷ 4) - (36 ÷ 9)

9 - 4

(8 × 3) - 12 = 12

24 - 12

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Round 21 to the nearest 10.

bagirrra123 [75]

21 rounded to the nearest 10 is 20 :)

4 0

3 years ago

Read 2 more answers

Help me please !!!!!!!

KATRIN_1 [288]

Answer:

m<ACB = 107*

Step-by-step explanation:

First we have to find the angle of m<CEB.

We know that the value of that angle plus m<CEP equals a total of 180, so we subtract the value that we have (147*) from 180 and we get 33*.

33* Is also the value of m<CAB.

33+40 = 43. 180-43 = 107.

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2 years ago

Find the length of XY bisector

Rzqust [24]

Answer:

We'd need to know the coordinates of the line segment.

4 0

3 years ago

Simplify the following question

fiasKO [112]

Answer:

<em>− 2sin(b) / cos(2b)</em>

Step-by-step explanation:

DIFFERENTIATE W.R.T. B is a different method entirely

We simply add together the numerators and set with 2cos

then keep this number and add to sinb and square it.

then repeat initial 2 + cosb ^2 but instead of multiplying its add.

Then set the whole division to -sin (2b) squared then +1

<em> − 2cos(b)(3(sin(b))^2+(cos(b))^2) / −(sin(2b)) ^2 +1 </em>

5 0

2 years ago

during a softball game kay hit a fly ball the function f(x) = -16t^2 + 64t + 4 describes the height of the softball in feet. mak

STatiana [176]

<h2>Hello!</h2>

The graph is attached.

To graph a parabola we need to know the following:

- If the parabola is open upwards or downwards

- They axis intercepts (if they exist)

- The vertex position (point)

We are given the function:

$f(t)=-16t^{2}+64t+4$

Where,

$a=-16\\b=64\\c=4$

For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.

Finding the axis interception points:

Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:

$f(t)=-16t^{2}+64t+4\\0=-16t^{2}+64t+4\\-16t^{2}+64t+4=0$

Using the quadratic equation:

$\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}\\\\\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}=\frac{-64+-\sqrt{4096+256} }{-32}\\\\\frac{-64+-\sqrt{4096+256} }{-32}=\frac{-64+-(65.96) }{-32}\\\\t1=\frac{-64+(65.96) }{-32}=-0.06\\\\t2=\frac{-64-(65.96) }{-32}=4.0615$

So, at t=4.0615 the height of the softball will be 0.

Since we will work only with positive values of "x", since we are working with a function of time:

Let's start from "t" equals to 0 to "t" equals to 4.0615.

So, evaluating we have:

$f(0)=-16(0)^{2}+64(0)+4=4\\\\f(1)=-16(1)^{2}+64(1)+4=52\\\\f(2)=-16(2)^{2}+64(2)+4=68\\\\f(3)=-16(3)^{2}+64(3)+4=52\\\\f(4.061)=-16(4.0615)^{2}+64(4.0615)+4=0.0034=0$

Finally, we can conclude that:

- The softball reach its maximum height at t equals to 2. (68 feet)

- The softball hits the ground at t equals to 4.0615 (0 feet)

- At t equals to 0, the height of the softball is equal to 4 feet.

See the attached image for the graphic.

Have a nice day!

3 0

3 years ago