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inysia [295]
3 years ago
12

In the hotel room, Emily works on one of the field trip assignments. A certain

Mathematics
1 answer:
nikitadnepr [17]3 years ago
8 0
1 don’t trust me tho lol
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Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest
Licemer1 [7]

Answer:

$43.95

Step-by-step explanation:

15/100 × 293

= 43.95

7 0
3 years ago
Read 2 more answers
The base of a solid in the xy-plane is the first-quadrant region bounded y = x and y = x^2. Cross sections of the solid perpendi
musickatia [10]
Check the picture below.

thus, if one side on the square is x - x², then the area for the square is (x - x²)(x - x²), or (x - x²)²

now... what is the "x" value for the region, let's check their intersection.

\bf \begin{cases}
y=x\\
y=x^2
\end{cases}\implies x=x^2\implies 0=x^2-x\implies 0=x(x-1)
\\\\\\
x=
\begin{cases}
0\\
1
\end{cases}\\\\
-------------------------------\\\\
\displaystyle \int\limits_{0}^{1}\ (x-x^2)^2\cdot dx\implies \int\limits_{0}^{1}\ (x^2-2x^3+x^4)\cdot dx
\\\\\\
\cfrac{x^2}{2}-\cfrac{2x^4}{4}+\cfrac{x^5}{5}\implies \left. \cfrac{x^2}{2}-\cfrac{x^4}{2}+\cfrac{x^5}{5} \right]_{0}^{1}\implies \left[ \cfrac{1}{2}-\cfrac{1}{2}+\cfrac{1}{5} \right]-[0]\implies \cfrac{1}{5}

4 0
3 years ago
Read 2 more answers
K/2 + 1/2 = 3 what does the k=
sukhopar [10]

You multiply all the numbers by 2 to get rid of the fractions. This would leave you with k + 1 = 6. Then you subtract 1 from both sides to get k = 5.

5 0
3 years ago
Mr.Giarmo left for work at 7:15 A.M. Twenty-five minutes later ,he arrived at his work .What time did Mr. Giarmo arrive at his w
GuDViN [60]
All you have to do is add 25 to 15.

25+15=40

So, the time he arrives at work is at 7:40 AM.
4 0
4 years ago
Read 2 more answers
A rectangular patio has a length that is 4 times its width and has an area of 5000 square feet. What is the width of the patio?
dimaraw [331]

\bf \underline{ \underline{Given : }}

  • A rectangular patio has a length that is 4 times its width.

  • Area of rectangular patio is 5000 square feet.

\bf \underline{ \underline{To  \: be  \: calculated :  }}

Calculate the width of the patio.

\bf \underline{ \underline{Solution : }}

Let the width be a.

Then,Length = 4a

<u>According</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>question</u><u>, </u>

<u>\sf \: Area  \: of \:  rectangle = 5000 \:  ft {}^{2}</u>

\sf \implies \: Length  \times  Width  = 5000

Substituting the values of Length and width, we get..

\sf \implies 4a \times a = 5000

\sf \implies4 {a}^{2}  = 5000

\sf\implies \:  {a}^{2}  =  \cancel \dfrac{5000}{4}

\sf\implies \:  {a}^{2}  = 1250

\sf \implies \: a =  \sqrt{1250}

\sf \implies \: a = 35.35 \:  \: (approx)

\sf\therefore \: The \: width  \: of \:  rectangular  \: patio \:  is  \: 35.35 \: ft

3 0
3 years ago
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