Answer:
mean for a = 60/10 = 6
mad of a = 2
mean for b = 80/10 = 8
mad of b = 2
Step-by-step explanation:
Mean absolute deviation (MAD) of a data set is the average distance between each data value and the mean. Take each number in the data set, subtract the mean, and take the absolute value. Then take the sum of the absolute values. Now compute the mean absolute deviation by dividing the sum above by the total number of values in the data set. The mean absolute deviation, MAD, is 2.
\frac {1}{n} \sum \limits_{i=1}^n |x_i-m(X)|
m(X) = average value of the data set
n = number of data values
x_i = data values in the set
mean = average.
I thin the answer is D.DF
The label could be written in the area marked X as "Uses a convex eyepiece lens". Then the correct option is D.
<h3>What are Sets?</h3>
Sets are the collection of well-defined elements. A set is represented by a capital letter symbol and the number of elements in the finite set is shown as curly bracket {..}.
<h3>What is the Venn diagram?</h3>
It is the representation of the sets by the diagram. And shows the condition that is generated between them by the overlapping of the circle.
Shanti began to draw a Venn diagram comparing refracting and reflecting telescopes. The two overlapping circles.
The left circle is labeled Refracting telescopes.
The right circle is labeled Reflecting Telescopes.
An X in the overlap. Both as a label below and outside the overlap.
From the figure, we can say that the label could be written in the area marked X as "Uses a convex eyepiece lens".
Then the correct option is D.
More about the set link is given below.
brainly.com/question/8053622
= <span>(-8x - 9)(-9x2 + 7x - 9)
= 72x</span>³ - 56x² + 72x + 81x² - 63x + 81
= 72x³ + 25x² + 9x + 81
In short, Your Answer would be: Option D
Hope this helps!
This is describing how your graph should be numbered. If I understand it, it is saying that your y-axis should be numbered by 2s while your x-axis should be numbered by 1s.
Below, I have attached an example graph that may help you understand.