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3 years ago

Write the equation for:

Mathematics

1 answer:

xenn [34]3 years ago

7 0

Answer:

$\frac{1}{2} x +x = 2 (x-4)$

Step-by-step explanation:

Suppose number is x

Following equation can be written from question statement

$\frac{1}{2} x +x = 2 (x-4)$

Simplifying it further

$\frac{3}{2} x = 2x-8$

$\frac{3}{2} x -2x=-8$

$\frac{3x-4x}{2}= -8$

$-x= -16\\x=16$

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-3 1/6 divide by (-2 1/3)

marshall27 [118]

Answer:

1 5/14

Step-by-step explanation:

-3 1/6 / -2 1/3

-3 1/6 = -19/6

-2 1/3 = -7/3

-19/6 / -7/3 = -19/6 x -3/7

-19 x -3 = 57

-6 x -7 = 42

57/42 = 1 5/14

6 0

3 years ago

How do i do 3 part a ?

WINSTONCH [101]

In general the binomial expansion is

$(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0$

So in our case, because we want ascending powers of x we'll write,

$(-3x + 1)^{11} = {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9 + {11 \choose 3 } (-3x)^3 1^8 + ...$

We need to calculate the binomial coefficients:

${11 \choose 0} = 1$

${11 \choose 1} = 11$

${11 \choose 2} = \dfrac{11 \times 10}{2} = 55$

${11 \choose 3} = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165$

$(-3x+1)^{11} = 1 (-3x)^0 1^{11} + 11(-3x)^{1} 1^{10} + 55 (-3x)^2 1^{9} + 165 (-3x)^3 1^8 + ...$

$(1-3x)^{11} = 1 -33 x + 495 3x^2 - 4455 x^3+ ...$

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slava [35]

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Read 2 more answers

1 over 3 + 3 over 8 = what

Simora [160]

It could be 17/24 but you may need to simplify

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3 years ago