Is 137 degrees the same as c degrees? If not, someone explain please.

Ill mark you as brainlist just please answer

RSB [31]

Answer:

b one is the answer

Step-by-step explanation:

4 0

3 years ago

Is 3n a cubic a quadratic a linear or none of these

lilavasa [31]

Step-by-step explanation:

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Class 10

>>Maths

>>Polynomials

>>Revisiting Polynomials

>>Classify the following as linear, quadra

Question

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Classify the following as linear, quadratic and cubic polynomials:

(i) x

2

+x

(ii) x−x

3

(Iii) y+y

2

+4

(iv) 1+x

(v) 3t

(vi) r

2

(vii) 7x

3

Medium

Solution

verified

Verified by Toppr

(i) The highest degree of x

2

+x is 2, so it is a quadratic polynomials.

(ii) The highest degree of x−x

3

is 3, so it is a cubic polynomials.

(iii)The highest degree of y+y

2

+4 is 2, so it is a quadratic polynomials.

(iv) The highest degree of x in (1+x) is 1, so it is a linear polynomials.

(v)The highest degree of t in 3t is 1, so it is a linear polynomials.

(vi)The highest degree of r

2

is 2, so it is a quadratic polynomials.

(vii)The highest degree of x in 7x

3

is 3, so it is a cubic polynomials.

Video Explanation

7 0

2 years ago

A fox charge of $50 per job, plus. An hourly charge of $80 per hour. What is umesh’s total charge in dollars. C relates to the n

Contact [7]

Given: C -> Umesh's total charge in dollars. h -> the number of hours he spends on a job. Hourly charge =$80 /hr Charge for h hours = 80*h fixed charge per job = $50 Therefore, C = 80h +50 is the required equation to find the total charges

8 0

3 years ago

What is the ratio of course to cups in a carton of milk

deff fn [24]

Well, the way I would do this is count the course and write that first, than put the 2 colins and than the carton of milk ratio. I hope this helped!

7 0

3 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

2 years ago