Answer:
9.86 inches
Step-by-step explanation:
Given:
The cup will be a right circular cone with:-
Radius, r = 3 inches
Volume of cone = 93 cubic inches
Height of the cup, h = ?
Solution:
<u>By using :-</u>
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By dividing both sides by 9.43
Thus, the cup need to be 9.86 inches taller to hold 93 cubic inches of water.
Answer:
-9
Step-by-step explanation:
The mode is the value that appears most often in a set of numbers, and the number -9 appears the most in this set.
Answer:
A. He will have to work 40 hours to buy the headphones
B. 1200 ≤ 10.25x ≤ 2000 where x is # of hrs worked
He can work anywhere between 118 and 196 hours.
Step-by-step explanation:
A. Divide 399.95 by 10.25 to get 39.01 hours. But since you cant work 0.01 of an hour, you have to round up to the next hour
B. You want to make more than or equal to 1200, so put that in the inequality. You want to make less or equal to 2000, so you put that in the inequality. In the middle, you put 10.25 an hour multiplied by the number of hours, which is a variable.
To solve, I made 10.25x = 1200, and x equaled 117.07, which rounds up to 118 hours because you cant work a 0.07 of an hour. 118 hours is the low number of the spectrum.
To solve for the highest number on the spectrum, you do 10.25x = 2000, and x equals 195.12, but since you cant work 0.12 of an hour, it rounds up to 196 hours.
Answer:
<u><em>canvases over weeks
</em></u>
<u><em>
</em></u>
<u><em>Step-by-step explanation:
</em></u>
<u><em>
</em></u>
<u><em>Given:
</em></u>
<u><em>
</em></u>
<u><em>w(h) represents how many hours per week
</em></u>
<u><em>
</em></u>
<u><em>c(t) approximates how many canvases she paints per hour
</em></u>
<u><em>
</em></u>
<u><em>In function composition, if we have two function f(x) and g(x) then
</em></u>
<u><em>
</em></u>
<u><em>(f.g)(x) or f(g(x)) means first apply g(), then apply f() i.e. applying function f to the results of function g.
</em></u>
<u><em>
</em></u>
<u><em>Now we have c(w(h)), this means first we apply w(h) which will give us hours per week and then we'll apply function 'c' on the results of 'w' (that is number of hours for weeks painted). As result we'll get number of canvas </em></u>per week!
