Answer: 272
Step-by-step explanation:
Let a1=11
a2=20
a3=29
Formula for sequence=
an=a1+(n-1)d
an = nth term
a1= first term
n= nth position
d= common difference
We are looking for the 30th term,so our n=30
d= a2-a1
d= 20-11
d= 9
Using the formula
an= a1+(n-1)d
a30= 11+(30-1)9
a30= 11+(29)9
a30= 11+(29×9)
a30= 11+261
a30= 272
Therefore, the 30th term is 272
The exponential function that passes through (0,2) and (3,54) is a growth function
The exponetial function is y = 2 * 3^x
<h3>How to construct the exponential function?</h3>
The points are given as:
(x,y) = (0,2) and (3,54)
An exponential function is represented as:
y = ab^x
Substitute the points in the equation
2 = ab^0 and 54 = ab^3
Solve 2 = ab^0
a = 2
Substitute 2 for a in 54 = ab^3
54 = 2b^3
Divide by 2
27 = b^3
Take the cube roots of both sides
b = 3
So, we have:
y = ab^x
This becomes
y = 2 * 3^x
Hence, the exponetial function is y = 2 * 3^x
Read more about exponential functions at:
brainly.com/question/24077767
An= A1 r ^(n-1)
An= -4 (-3)^(n-1)
An= -4 (-3)^(7-1)
An= -4 (729)
An= -2916
I think this is right :)
Do you have a picture? i can help if you have one
(3x-5)+(x+1)=180
x=46
3(46)-5=133
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