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3 years ago

Solve for X 5x-2x-1/2=3x+x-2/2

Mathematics

1 answer:

navik [9.2K]3 years ago

3 0

Answer:

(2x-2/2) = (15-6x)

2x-1 = 15 -6x

2x+6x = 15 +1

8x = 16

8x/8 = 16 /8

x = 2 there

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Answer:

A) Alternative hypothesis; Ha: p_o > ⅔

B) Null hypothesis;

H0: p_o = ⅔

C) There is sufficient evidence to support the claim that the community screening programme was effective

D) p-value = 0

Its less than the significance value and so we will reject the null hypothesis and conclude that the community screening programme was effective

Step-by-step explanation:

A) We are told that ⅓ of those diagnosed eventually die of the disease. Thus, ⅔ is the fraction that will survive the disease.

Thus, the null hypothesis is;

H0: p_o = ⅔

We are told that a screening programme was started to increase the survival rate. Thus,the alternative hypothesis is;

Ha: p_o > ⅔

B) null hypothesis is;

H0: p_o = ⅔

C) 164 out of the 200 women selected survived the disease.

Thus sample proportion is;

p^ = 164/200

p^ = 0.82

For the z-score value, we will use the formula;

z = (p^ - p_o)/√((p_o(1 - p_o)/n)

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Thus;

z = (0.82 - 0.67)/√((0.67(1 - 0.67)/200)

z = 4.51

From online p-value from z-score calculator, we have p-value ≈ 0

This is less than the significant level of 0.05 and therefore we will reject the null hypothesis and conclude that the community screening program was effective.

D) p-value ≈ 0

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3 years ago

A sample of 260 students enrolled at a university were asked what they intended to do after graduation. The results are shown be

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ANSWER

$30\%$

EXPLANATION

The total number of students can be calculated by adding all the frequencies.

From the graph the total frequency is,

$39+117+78+26 =260$

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The percentage of students who intend to go into state or local government after graduation

$= \frac{78}{260} \times 100\%$

$= \frac{3}{10} \times 100\%$

$= 30\%$

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So there are 52 horses
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3 years ago

Solve for X 5x-2x-1/2=3x+x-2/2​

Solve for X 5x-2x-1/2=3x+x-2/2