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4 years ago

How would I solve this?? Any help is much appreciated

Mathematics

1 answer:

kirill [66]4 years ago

4 0

Answer:

155 km

Step-by-step explanation:

As shown:

At Δ BDC which is a right triangle at ∠D

BC = 78 km

m∠CBD = 90° - 64° = 26°

cos ∠CBD = BD/BC

∴ BD = BC * cos ∠CBD = 78 * cos 26° = 70.106 km

Port C is at a distace to the east of A = AO + BD

= 85 + 70.106 = 155.106 km ≈ 155 km to the nearest km

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