What is the equation of the line that passes through point (4, 12) and has a y- intercept of -2?

Mathematics

1 answer:

Elan Coil [88]2 years ago

5 0

Answer:

y = (7/2)x - 2

Step-by-step explanation:

Use slope-intercept formula for linear equations y = mx + b

x and y show what points are on the line. We know (4, 12). x= 4 and y = 12

b is the y-intercept, which b = -2.

m is the slope.

To write the equation, you need the slope and y-intercept. Find the slope by putting x, y and b into the formula.

y = mx + b

12 = 4m - 2

14 = 4m

14/4 = m

m = 7/2

Put "m" into the formula with "b"

y = (7/2)x - 2

You might be interested in

Pleaseeeeeeeeeeee

Karo-lina-s [1.5K]

$\text{The scientific notation:}\\\\a\times10^n\\\\1\leq a$

$a.\\(5\times10^3)\times(3.5\times10^{-1})=(5\times3.5)\times(10^3\times10^{-1})\\\\=15.75\times10^{3+(-1)}=15.75\times10^2=1.575\times10\times10^2\\\\=1.575\times10^{1+2}=\boxed{1.575\times10^3}$

$b.\\(8\times10^2)\div(4\times10^3)=(8\div4)\times(10^2\div10^3)=2\times10^{2-3}\\\\=\boxed{2\times10^{-1}}$

$c.\\(6\times10^{-3})^2=6^2\times(10^{-3})^2=36\times10^{-3\cdot2}=36\times10^{-6}=3.6\times10\times10^{-6}\\\\=3.6\times10^{1+(-6)}=\boxed{3.6\times10^{-5}}$