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pashok25 [27]
3 years ago
8

If 3 hens lay 10 eggs in 5 days, how many eggs will 3 hen lay in 20 days.

Mathematics
2 answers:
Ivan3 years ago
6 0

Answer:

the answer is 40 eggs.

Step-by-step explanation:

5 = 10

20 divided by 5 = 4

10 x 4 = 40

hope it helps plz mark as brainliest

Bogdan [553]3 years ago
4 0

Answer:it would be 40 eggs

Step-by-step explanation:

10 divided by 5= 2(eggs per day)

Then times 2 by 20 to get the answer of 40 eggs in 20 days

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If you cross mulitply the answer would be 13.3
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3 years ago
Suppose the average yearly salary of an individual whose final degree is a​ master's is ​$41 thousand less than twice that of an
charle [14.2K]

Answer:

The average salary of master's degree people is $ 63,000    And

The average salary of bachelor's degree people is $ 52,000  

Step-by-step explanation:

Given in question as :

Let the average salary of master's degree people = $ M       And

Let the average salary of bachelor's degree people = $ B

According to question ,

The average salary of master's degree people + The average salary of bachelor's degree people  = $115,000

Or , $ M + $ B = $ 115,000                                 ............. A

Again ,

$ M = 2 × $ B - $ 41,000                             ............... B

From eq A and eq B

(2 × $ B - $ 41,000 )   +  ( $ B ) = $ 115,000

Or, 3×$ B = 156,000

∴        B = \frac{156,000}{3} = $ 52,000

And   M = $ 115,000 - $ 52,000

∴       M = $ 63,000

Hence The average salary of master's degree people is $ 63,000    And

           The average salary of bachelor's degree people is $ 52,000   Answer  

5 0
3 years ago
Find the x- and y-intercepts of the graph of 4x + 10y = 36. State your answers as
svetoff [14.1K]

Answer:

Step-by-step explanation:

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3 0
3 years ago
A fund earns a nominal rate of interest of 6\% compounded every two years. Calculate the amount that must be contributed now to
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Answer:

$712.

Step-by-step explanation:

We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,  

n = Number of times interest is compounded per year,

t = Time in years.

6\%=\frac{6}{100}=0.06

Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.

1000=P(1+\frac{0.06}{0.5})^{0.5*6}

1000=P(1+0.12)^{3}

1000=P(1.12)^{3}

1000=P*1.404928

\frac{1000}{1.404928}=\frac{P*1.404928}{1.404928}

P=711.7802478

P\approx 712

Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.

7 0
3 years ago
Geno signed up for a text messaging plan. He pays a $5.00 monthly fee and $0.04 per text message.
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Answer:

The correct answer is [C.) 0.04r + 5.00}

Step-by-step explanation:

hope this hlps

7 0
3 years ago
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