Question

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Answer 1

Answer:

h(-8) = -8

Step-by-step explanation:

Put x = -8 to the formula of h(x)

$h(x)=\dfrac{x^2+3x}{4x+27}\\\\h(-8)=\dfrac{(-8)^2+3(-8)}{4(-8)+27}=\dfrac{64-24}{-32+27}=\dfrac{40}{-5}=-8$