3 years ago

50 points and Brainliest for answer

Mathematics

2 answers:

Naddika [18.5K]3 years ago

8 0

Answer:

i dont know sorry

Step-by-step explanation:

kenny6666 [7]3 years ago

6 0

1st - function 2nd - not a function 3rd - function 4th - not a function 5th - function

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Find+the+positive+value+for+α+if+the+radius+of+the+circle+3x^2+3y-6αx+12y-3α=0+is+4

Alik [6]

Answer:

$\alpha=3$

Step-by-step explanation:

<u>Equation of a Circle</u>

A circle of radius r and centered on the point (h,k) can be expressed by the equation

$(x-h)^2+(y-k)^2=r^2$

We are given the equation of a circle as

$3x^2+3y^2-6\alpha x+12y-3\alpha=0$

Note we have corrected it by adding the square to the y. Simplify by 3

$x^2+y^2-2\alpha x+4y-\alpha=0$

Complete squares and rearrange:

$x^2-2\alpha x+y^2+4y=\alpha$

$x^2-2\alpha x+\alpha^2+y^2+4y+4=\alpha+\alpha^2+4$

$(x-\alpha)^2+(y+2)^2=r^2$

We can see that, if r=4, then

$\alpha+\alpha^2+4=16$

Or, equivalently

$\alpha^2+\alpha-12=0$

There are two solutions for $\alpha$ :

$\alpha=-4,\ \alpha=3$

Keeping the positive solution, as required:

$\boxed{\alpha=3}$

8 0

3 years ago

The smoothie shop offers five fruits strawberry, banana, pineapple, mango, and blueberry. If Tracy wants to order a smoothie wit

Paha777 [63]

15 I helped someone with this question already so I know its right

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3 years ago

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If jimmy had had 9 apples and karl has 10 how mush togheter

sveticcg [70]

19? Lol........................

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3 years ago

This circle is centered at the origin, and the length of its radius iS 6. What is

VikaD [51]

$\sf{\qquad\qquad\huge\underline{{\sf Answer}}}$

The equation of circle in standard form can be represented as :

$\qquad \sf \dashrightarrow \:(x - h) {}^{2} + (y - k) {}^{2} = r {}^{2}$

where,

h = x - coordinate of centre = 0

k = y - coordinate of centre = 0

r = radius of circle = 6 units

now, let's plug in the values :

$\qquad \sf \dashrightarrow \:(x - 0) {}^{2} + (y - 0) {}^{2} = 6 {}^{2}$

$\qquad \sf \dashrightarrow \: {x}^{2} + {y}^{2} = 36$

That's the required equation of circle.

4 0

2 years ago

Find all the powers of 3 that are in the range 3 through 1000

Ksivusya [100]

So just use a calculator but here goes
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243
3^6=729

and 3^7 is 2187 which is excluded

8 0

3 years ago