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blsea [12.9K]
3 years ago
5

Which story problem could be solved using the given equation? 14×35=m

Mathematics
2 answers:
melomori [17]3 years ago
6 0

Answer:

See explanation below

Step-by-step explanation:

We have a rectangle with a length of 14 feet and a width of 35 feet. What is the area m of this rectangle?

Since the area of a rectangle is given by the formula: length x width, the area for this problem would be 14 x 35.

Naming the area m, this would give us:

14 x 35 = m.

Art [367]3 years ago
4 0
"what is the product of 14 multiplied by 35?"
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Which ordered pair is the solution to the system of linear equations y = 5x+8 and Y = -4x-1?
White raven [17]

Answer:

(-1, 3)

Step-by-step explanation:

If you graph both lines, the point where they intersect is (-1,3)

4 0
3 years ago
8. Dylan has 35 coins in his pocket. All of them are either pennies or quarters, and
blsea [12.9K]
He has 17 quarters and 18 pennies.
Because 17*0.25=4.25 and 18*0.01=0.18.
4.25+0.18=4.43 also 17+18=35
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Irina18 [472]
Slope:5 y-intercept: -2

4 0
3 years ago
Brainliest + 20 pts to whoever helps pls!!
Blizzard [7]

Answer:

Correct option is (a). 60.391 and 101.879; because the test statistic is in a critical region, the test rejects the null hypothesis.

Step-by-step explanation:

A Chi-square test for population variance is used to perform this test.

The standard deviation is, 2.0 minutes.

Then the variance is, 4.0 minutes.

The hypothesis for this test is:

<em>H₀</em>: The population variance of all commute times is equal to 4.0 minutes, i.e. <em>σ² </em>= 4.

<em>Hₐ</em>: The population variance of all commute times is not equal to 4.0 minutes, i.e. <em>σ² </em>≠ 4.

The test statistic is:

\chi^{2}_{calc.}=\frac{(n-1)s^{2}}{\sigma^{2}}

The critical region of this test is defined as:

Reject <em>H₀</em> if \chi^{2}_{calc.} or \chi^{2}_{calc.}>\chi^{2}_{(1-\alpha /2), (n-1)}.

The degrees of freedom is:

n-1=81-1=80

Compute the critical from a Chi-square table.

\chi^{2}_{\alpha /2, (n-1)}=\chi^{2}_{0.05, 80}=101.879\\\chi^{2}_{(1-\alpha /2), (n-1)}=\chi^{2}_{0.95, 80}=60.391\\

The test statistic value is, \chi^{2}_{calc.}=105.8.

\chi^{2}_{calc.}=105.8 > \chi^{2}_{0.05, 80}=101.879

The null hypothesis is rejected because the test statistic is in the critical region.

Thus, the correct option is (a).

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3 years ago
Solve the equation. Check the solution. Use a graphing calculator. Select the correct choice and fill in any answer boxes in you
Maurinko [17]

The solution is x = -2.27 and x= 5.28

Let me attach the picture

6 0
1 year ago
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