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ehidna [41]
3 years ago
15

Pls who would like to be my friend. what is a limiting reagent?

Chemistry
1 answer:
Rzqust [24]3 years ago
7 0

Answer: The Limiting Reagent is the stuff that limits the solution of the reaction.

Ex: A potato pairs with a tomato. You have 4 potatoes and whatever amount of tomatoes, your solution will always for 4 pairs because potatoes is the <em>limited reagent.</em>

You might be interested in
Ethanol is a common laboratory solvent and has a density of 0.789 g/mL. What is the mass, in grams, of 139 mL of ethanol?
Luda [366]
Just use the equation M=DV which means Mass equals Density times Volume. Simply plug your values into the equation to get

M=.789(139) and solve
7 0
3 years ago
How many moles of O are present in 2.9 mol of Al2(SO4)3 ?
ad-work [718]

Answer:

34.8 moles of O

Explanation:

First we break down Al2(SO4)3 and look at SO4 only. In this compound, there are already 4 moles of O. Then you see that there are 3 moles of (SO4), meaning there are 3*4 moles of O = 12 moles in the entire compound. Then you look at the question, where it's asking for 2.9 moles of the entire Al2(SO4)3 compound, so you multiply 2.9*12 = 34.8 total moles of O.

6 0
4 years ago
How do you balance this chemical equation?
ryzh [129]
Ba(ClO3)2 --> BaCl2 + 3 O2

The fact that there are some ionic compounds doesn't matter. Just use the formulas.
barium chlorate = Ba(ClO3)2
barium chloride = BaCl2
Oxygen = O2

Now create the unbalanced equation
Ba(ClO3)2 --> BaCl2 + O2


And balance in the usual fashion. Count the atoms of each element on both sides
Ba = 1, 1
Cl = 2, 2
O = 6, 2

And oxygen is out of balance. But can be easily handled with a 3 coefficient on the right hand side. So:
Ba(ClO3)2 --> BaCl2 + 3 O2

And we have a balanced equation.
6 0
4 years ago
The formula for a compound of Li+ ions and Br- ions is written LiBr. Why can’t it be written Li2Br? Why isn’t it written BrLi?
maksim [4K]

Lithium has charge of +1 and bromide has charge of - 1. So they combine to form the compound lithium bromide which is expressed as LiBr.

<h3><u>Explanation:</u></h3>

Lithium is an alkali metal placed in group 1 or periodic table. It has a valency of 1 which is achieved as lithium loses an electron to achieve a charge of +1.

Bromine is a halogen which is placed in group 17 of periodic table. It has a valency of 1 which is achieved as bromine looses an election to achieve a charge of - 1.

Lithium is the cation and bromide is the anion. So lithium is written in front and bromine following the cation. And as both of their valencies are 1, so they form the compound LiBr.

3 0
3 years ago
Imagine that A and B are cations and X, Y, and Z are anions, and that the following reactions occur: AX(aq)+BY(aq)→no precipitat
aleksley [76]

Answer:

b. AZ BX

Explanation:

A⁺, B⁺, X⁻, Y⁻ and Z⁻

AX(aq)+BY(aq)→no precipitate

AX(aq)+BZ(aq)→precipitate.

AX(aq)+BY(aq)→no precipitate:

A⁺ (aq) + X⁻ (aq) + B⁺ (aq) + Y⁻ (aq) → AY (aq) + BX (aq)

AX(aq)+BZ(aq)→precipitate:

A⁺ (aq) + X⁻ (aq) + B⁺ (aq) + Z⁻ (aq) → AZ (s) + BX (aq)

Considering the reactions above, the insoluble specie is AZ.

3 0
3 years ago
Read 2 more answers
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