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Answer:
Any substance which occupies space and has mass is known as matter. States of matter: Matter exist in three different states that are Solid, Liquid and Gas. Matter is made up of very small particles
Explanation:
Answer : The value of 'R' is 
Solution : Given,
At STP conditions,
Pressure = 1 atm
Temperature = 273 K
Number of moles = 1 mole
Volume = 22.4 L
Formula used : 
where,
R = Gas constant
P = pressure of gas
T = temperature of gas
V = volume of gas
n = number of moles of gas
Now put all the given values in this formula, we get the values of 'R'.
Therefore, the value of 'R' is .
Answer:
929.4 kJ of heat is released.
Explanation:
The enthalpy of vaporization of hydrogen sulfide is 18.7 kJ/mol at -60.0 °C.
The data explains that 1 mol of H₂S uses 18.7 kJ of energy in vaporization.
By the Ideal Gas Law, we can know, how many moles do we have, of gas.
P. V = n . R . T
87 atm . 10L = n . 0.0821 L.atm/K.mol . 213 K
(87 atm . 10L) / (0.0821 K.mol/L.atm . 213 K) = 49.7 moles
1 mol ____ 18.7 kJ
49.7 moles _____ (49.7 . 18.7) = 929.4 kJ
Chemical reaction
C2H2(g) + H2O(g) ⇄ CH2CHO(g)
a) Removing H2O(g) from the system
Remember that Le Chatelier principle states that when an equilibrium is disturbed the system will try to counteract to restate the equilibrim.
If you remove H2O(g) then the equilibrium will be displaced to the left, trying to produce more H2O(g), which means to reduce CH3CHO(g) and increasing the C2H2(g).
b) Adding CH3CHO(g)
To counteract the addition of CH3CHO(g) the system will try to regain equilibrium by producing more reactants: C2H2(g) and H2O(g)
c) Removing C2H2(g)
The system will again displace to the left, that is CH3CHO(g) will reduce and H2O(g) will increase.
d) Adding H2O(g)
The systmen will displace to the right reducing C2H2(g) and increasing CH3CHO(g).
