1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maxonik [38]
3 years ago
13

A major problem associated with the incomplete combustion of soft coal is pollution.

Chemistry
2 answers:
spayn [35]3 years ago
8 0
A major problem associated with the incomplete combustion of soft coal is pollution. True
kodGreya [7K]3 years ago
5 0

Answer

True

Explanation:

You might be interested in
4NH3(g) + 3O2(g) --> 2N2(g) + 6H2O(l)
slamgirl [31]

Answer:

the right answer is : d

Explanation:

Because temperature is a cinetic factor.

3 0
3 years ago
Give me Investigating questions that have dependent variable independent variable and control variable
Masteriza [31]

Answer:

What type of soil filters water best?

Explanation:

dependent variable - the cleanliness of the water after it is filtered

independent variable - soil

control variable - water

(Asking with a <em>please </em>wouldn't hurt -_-)

4 0
3 years ago
What is the mass in 6.34x10^23 molecules of calcium chloride
Liono4ka [1.6K]

Answer : The mass of calcium chloride is, 116.84 grams

Solution : Given,

Molar mass of calcium chloride, CaCl_2 = 110.98 g/mole

Number of molecules of calcium chloride = 6.34\times 10^{23}

As we know that,

1 mole of calcium chloride contains 6.022\times 10^{23} molecules of calcium chloride

or,

1 mole of calcium chloride contains 110.98 grams of calcium chloride

Or, we can say that

As, 6.022\times 10^{23} molecules of calcium chloride present in 110.98 grams of calcium chloride

So, 6.34\times 10^{23} molecules of calcium chloride present in \frac{6.34\times 10^{23}}{6.022\times 10^{23}}\times 110.98=116.84grams of calcium chloride

Therefore, the mass of calcium chloride is, 116.84 grams

6 0
3 years ago
A 36.165 mg36.165 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion an
erma4kov [3.2K]

Answer:

The empirical formula for the compound is C6H12SO2.

Explanation:

We'll begin by writing out what was given from the question. This is shown:

Let us consider the First experiment:

Mass of the compound = 36.165 mg

Mass of CO2 = 64.425 mg

Mass of H2O = 26.373 mg

Data obtained from the Second experiment:

Mass of compound = 47.029 mg

Mass of SO2 = 20.32 mg

Next, we'll determine the mass of C, H and S. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C in CO2 = 12/44 x 64.425 Mass of C = 17.57 mg

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of H in H2O = 2/18 x 26.373

Mass of H = 2.93 mg

Molar Mass of SO2 = 32 + (16x2) = 64g/mol

Mass of S in SO2 = 32/64 x 20.32

Mass of S = 10.16 mg

At this stage, it is important we determine the percentage composition of C, H, S and O. This is illustrated below:

% of C = 17.57/36.165 x 100 = 48.58%

% of H = 2.93/36.165 x 100 = 8.10%

% of S = 10.16/47.029 x 100 = 21.60%

% of O = 100 - (48.58 + 8.1 + 21.6)

% of O = 21.72%

Now we can easily obtain the empirical formula for the compound by doing the following.

Step 1:

Divide by their molar mass

C = 48.58/12 = 4.0483

H = 8.10/1 = 8.1

S = 21.60/32 = 0.675

O = 21.72/16 = 1.3575

Step 2:

Divide by the smallest:

C = 4.0483/0.675 = 6

H = 8.1/0.675 = 12

S = 0.675/0.675 = 1

O = 1.3575/0.675 = 2

From the calculations made above, empirical formula for the compound is C6H12SO2

7 0
3 years ago
A
Artemon [7]

Answer:

9.8ms^{-2}

Explanation:

using the equation :

acceleration = \frac{final  velocity - initial velocity}{timetaken} \\                      a  =\frac{v-u}{t}

where v is 98m/s

u is 0m/s

t is 10seconds

a=\frac{98m/s- 0m/s}{10} \\a=\frac{98}{10}\\ a=9.8m/s^{2}

3 0
2 years ago
Other questions:
  • An atomic number stands for the number of _____.
    5·2 answers
  • Ethanol is a common laboratory solvent and has a density of 0.789 g/ml. What is the mass, in grams, of 125 ml of ethanol?
    15·1 answer
  • Number 11 please fast answer
    6·2 answers
  • How is diffusion used by cells? (Missed this lesson in school)
    10·2 answers
  • A student measured a strip of aluminum as 1.25m long. The teacher said it was actually 2.12m long. What was the student's percen
    7·1 answer
  • HELPPPPPPPP PLZZZZ MVP ME .!!!
    15·1 answer
  • What is force and it's so unit?<br>​
    14·1 answer
  • CH3 + O2 ---) CO2 + H20 Is this balanced or unbalanced?
    7·1 answer
  • 3. How is the potential energy of any object released? What happens to this released energy? I
    6·1 answer
  • What is a Bohr model?
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!