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3 years ago

How are radius and diameter related

Physics

1 answer:

Vinvika [58]3 years ago

3 0

The radius of a circle is the distance from the center of a circle to any point of a circle.

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2. In contrast to Venus, the coldest temperature yet measured on the surface of

garik1379 [7]

Answer:

Explanation:

<u>Temperature Scales </u>

There are three temperature scales in the modern sciences: Fahrenheit, Celsius, and Kelvin. Fahrenheit temperature scale assigns the value 32 for the freezing point of water and 212 for the boiling point of water and divides that interval into 180 parts. Celsius scale has a similar reference, giving 0 to the freezing point of water and 100 for the boiling point of water. The conversion between them is as follows

$\displaystyle F=\frac{9}{5}C+32$

$K=C+273.15$

The coldest temperature yet measured on the surface of any body in the solar system is -235°C. Converting to Fahrenheit

$\displaystyle F=\frac{9}{5}(-235)+32=-391^oF$

$K=-235+273.15=38.15^oK$

4 0

3 years ago

What is the attraction between atoms when they react called?

nekit [7.7K]

Answer:

Chemical bond

Explanation

3 0

3 years ago

Read 2 more answers

A block with a mass of 9.00 kg is pulled at a constant speed across a horizontal tabletop with a spring scale. The scale reads 6

snow_tiger [21]

Answer:0.69

Explanation:

Coefficient of kinetic friction=f/R=61.8/90=0.69

7 0

3 years ago

Decelerating cor, driver having taken his foot off the accelerator and applying <br>brakes

Dmitry [639]

Explanation:

In a manual transmission there are three pedals. From left to right, they are: Clutch, Brake, Gas. The clutch is the only pedal you press with your left foot. The other pedals – brake and gas – operate just like they do in an automatic transmission.

6 0

3 years ago

A green block of mass m slides to the right on a frictionless floor and collides elastically with a red block of mass M which is

igor_vitrenko [27]

Answer: M is equal to m.

Explanation:

The question gives us two important informations:

M is initially at rest
m finishes at rest after collision.

In any collision, as it is asumed that no external forces can act during the collision, momentum must be conserved.

So, if we call p₁ to the momentum before collision, and p₂ to momentum after it, taking into account the information above, we can write the following:

p₁ = mv₁ + M.0 = p₂ = m.0 + Mv₂ ⇒ mv₁ = Mv₂

From the question, we also know that it was an elastic collision.

In elastic collision, added to the momentum conservation, it must be conserved the kinetic energy also.

So, if we call k₁ to the kinetic energy prior the collision, and k₂ to the one after it, we can write the following:

k₁ = 1/2 m(v₁)² + 1/2 M.0 = k₂ = 1/2m.0 + 1/2M(v₂)² ⇒ m(v₁)² = M(v₂)²

Mathematically, the only way in which both equations be true, should be with v₁ = v₂, which is only possible if m=M too.

In this type of collision, it is said that the energy transfers from one mass to the other.

7 0

3 years ago