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3 years ago

What type of star is the sun?

Physics

2 answers:

SashulF [63]3 years ago

8 0

C. main sequence is what the test tells me.

Hope this helps

finlep [7]3 years ago

5 0

I believe the correct answer from the choices listed above is option B. The sun is a main sequence type of star. <span>The sun is classified as a G2V star, sometimes referred to as a yellow dwarf. It is a Population I star in its main </span>sequence<span>. Hope this answers the question.</span>

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Calculate the speed of a 3.5cm sound wave of frequency 8000Hz

LuckyWell [14K]

The answer to this question is 2400Hz

8 0

3 years ago

Read 2 more answers

When illuminated with monochromatic light, a double slit produces a pattern that is a combination of single-slit diffraction and

d1i1m1o1n [39]

Answer:

The ratio is $k:d = 1 : 5$

Explanation:

From the question we are told that

The first minimum of the single slit pattern falls on the fifth maximum of the double slit pattern.

Generally the condition for constructive interference for as single slit is

$ksin(\theta) = n\lambda$

Here k is the width of the slit and n is the order of the fringe and for single slit n = 1 (cause we are considering the first maxima)

Generally the condition for constructive interference for as double slit is

$dsin\theta = m\lambda$

Here d is the separation between the slit and m is the order of the fringe and for double slit m = 5 (cause we are considering the first maxima)

=> $dsin\theta = 5\lambda$

$\frac{ksin(\theta)}{dsin(\theta)} = \frac{\lambda}{5\lambda}$

=> $\frac{k }{d} = \frac{1}{5}$

$k:d = 1 : 5$

5 0

3 years ago

Under which conditions are particles in a medium said to be in phase with one another?

rewona [7]

Answer:

Corvette Corvette

Explanation:

teehee

The answer is A btw :)

7 0

3 years ago

What is the potential energy of two electrons that are separated by a distance of 3.5 x 10^-11m ?

Simora [160]

Answer:

6.58×10⁻¹⁸ J

Explanation:

Applying

E = kq²/r.................. Equation 1

Where E = potential energy, q = charge on each electron, r = distance between the electron, k = coulomb's constant.

From the question,

Given: r = 3.5×10⁻¹¹ m,

Constant: q = 1.6×10⁻¹⁹ C, k = 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

E = (1.6×10⁻¹⁹)²(8.99×10⁹)/(3.5×10⁻¹¹)

E = 6.58×10⁻¹⁸ J

4 0

3 years ago

a banana boat accelerates from 4.167 m/s ar 2.00m/s^2.How far has it traveled when it reaches 8.333 m/s

Nataly_w [17]

Answer: The distance that we'll be travelled is d=16.35m

Explanation: The main idea here is to use the equation of motion. We are given the acceleration of 2m/s^2,the initial and final velocies. The formula to use is v^2=u^2+2as. Now we have to substitute the values.

2^2= 8.33^2+2(2)d

d= 16.35m

8 0

4 years ago